(3): Parallel plate capacitor Q4. A capacitor of initially capacitance 0.08pF is filled with dielectric. The table behind gives the dielectric constant of the material inside the capacitor equals; applied voltage difference V on the capacitor as a function of its charge Q. The (a) 1.38 (c) 2.20 Q5. TI (b) 5.64 (d) 1:43 V (volts) 50 100 9 (PC) 5 10.5
(3): Parallel plate capacitor Q4. A capacitor of initially capacitance 0.08pF is filled with dielectric. The table behind gives the dielectric constant of the material inside the capacitor equals; applied voltage difference V on the capacitor as a function of its charge Q. The (a) 1.38 (c) 2.20 Q5. TI (b) 5.64 (d) 1:43 V (volts) 50 100 9 (PC) 5 10.5
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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please solve queeeestion 4

Transcribed Image Text:Problem (3): Parallel plate capacitor
Q4. A capacitor of initially capacitance 0.08pF is filled with dielectric. The table behind gives the
dielectric constant of the material inside the capacitor equals;
applied voltage difference V on the capacitor as a function of its charge Q. The
(a) 1.38
(c) 2.20
Q5. The presence of the dielectric material inside the capacitor will;
(a) Decrease its capacitance.
(c) Increase its voltage.
(b) 5.64
(d) 1.42
Problem (4): Kirchhoff's rul
In the figu
(b) Increase its capacitance.
(d) Decrease its charge.
Fig (1)
V (volts)
50
100
150
200
Q (PC)
5
10.5
16
21.5
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