3) Now there are three test tubes without labels, and the solutions are Na₂SO₄, Na₃PO₄, and Na₂CO₃. To determine and label, you have added Ba(NO₃)₂ to the three solutions and found all of them turned to white precipitate and failed to discriminate. In this situation, how would you do that?

We have three equations as follows 1- Reaction of Na2SO4 with Ba(NO3)2 Na2SO4 + Ba(NO3)2→NaNO3…

3) Now there are three test tubes without labels and the solutions are Na SO4, NA3PO4, and Na2CO3. To determine and label, you have added Ba(NO3)2 into three solutions and found all of them turned to white precipitate and failed to discriminate. In this situation, how would you do that?

3) Now there are three test tubes without labels and the solutions are Na SO4, NA3PO4, and Na2CO3. To determine and label, you have added Ba(NO3)2 into three solutions and found all of them turned to white precipitate and failed to discriminate. In this situation, how would you do that?

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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27.
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