3 Let a, b c and d be real numbers. Show that ab-cd = b(a−c)+c(b-d), and deduce that |ab − cd| ≤ |b||a – c| + |c||b − d\. - Let €, K and L be positive real numbers, and suppose that |b| < K, |c| < L, \a − c\ < €/(2K), [b−d] < €/(2L). Deduce that |ab− cd| < €.
3 Let a, b c and d be real numbers. Show that ab-cd = b(a−c)+c(b-d), and deduce that |ab − cd| ≤ |b||a – c| + |c||b − d\. - Let €, K and L be positive real numbers, and suppose that |b| < K, |c| < L, \a − c\ < €/(2K), [b−d] < €/(2L). Deduce that |ab− cd| < €.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please give me answers in 5min I will give you like sure
![1.23 Let a, b c and d be real numbers. Show that ab-cd = b(a−c)+c(b−d),
and deduce that
|ab − cd| ≤ |b||a − c| + |c||b − d|.
Let E,
K and L be positive real numbers, and suppose that |b| < K,
|c| < L, \a − c] < €/(2K), |b−d| < €/(2L). Deduce that |ab − cd| < €.
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Faaed6e9c-dce1-4b09-8cf0-c81cdcf3a73f%2Fd0907404-a947-4f60-ad69-c3dd5bb2a6a0%2Fzwmzaiw_processed.png&w=3840&q=75)
Transcribed Image Text:1.23 Let a, b c and d be real numbers. Show that ab-cd = b(a−c)+c(b−d),
and deduce that
|ab − cd| ≤ |b||a − c| + |c||b − d|.
Let E,
K and L be positive real numbers, and suppose that |b| < K,
|c| < L, \a − c] < €/(2K), |b−d| < €/(2L). Deduce that |ab − cd| < €.
-
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