3) Let å = 2ỉ +j,b = 5ỉ – 4j and c = i+j are vectors in 2D, then simplify å + b + 3č

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question

3

**Problem Statement:**

3) Let \(\vec{a} = 2\vec{i} + \vec{j}\), \(\vec{b} = 5\vec{i} - 4\vec{j}\) and \(\vec{c} = \vec{i} + \vec{j}\) be vectors in 2D. Simplify \(\vec{a} + \vec{b} + 3\vec{c}\) and write in component form. 

**Solution:**

Given:
- \(\vec{a} = 2\vec{i} + \vec{j}\)
- \(\vec{b} = 5\vec{i} - 4\vec{j}\)
- \(\vec{c} = \vec{i} + \vec{j}\)

First, compute \(3\vec{c}\):
\[
3\vec{c} = 3(\vec{i} + \vec{j}) = 3\vec{i} + 3\vec{j}
\]

Now, add \(\vec{a}\), \(\vec{b}\), and \(3\vec{c}\):
\[
\vec{a} + \vec{b} + 3\vec{c} = (2\vec{i} + \vec{j}) + (5\vec{i} - 4\vec{j}) + (3\vec{i} + 3\vec{j})
\]

Combine the components:
- \(i\)-components: \(2 + 5 + 3 = 10\)
- \(j\)-components: \(1 - 4 + 3 = 0\)

Thus, the simplified vector in component form is:
\[
10\vec{i} + 0\vec{j} = 10\vec{i}
\]
Transcribed Image Text:**Problem Statement:** 3) Let \(\vec{a} = 2\vec{i} + \vec{j}\), \(\vec{b} = 5\vec{i} - 4\vec{j}\) and \(\vec{c} = \vec{i} + \vec{j}\) be vectors in 2D. Simplify \(\vec{a} + \vec{b} + 3\vec{c}\) and write in component form. **Solution:** Given: - \(\vec{a} = 2\vec{i} + \vec{j}\) - \(\vec{b} = 5\vec{i} - 4\vec{j}\) - \(\vec{c} = \vec{i} + \vec{j}\) First, compute \(3\vec{c}\): \[ 3\vec{c} = 3(\vec{i} + \vec{j}) = 3\vec{i} + 3\vec{j} \] Now, add \(\vec{a}\), \(\vec{b}\), and \(3\vec{c}\): \[ \vec{a} + \vec{b} + 3\vec{c} = (2\vec{i} + \vec{j}) + (5\vec{i} - 4\vec{j}) + (3\vec{i} + 3\vec{j}) \] Combine the components: - \(i\)-components: \(2 + 5 + 3 = 10\) - \(j\)-components: \(1 - 4 + 3 = 0\) Thus, the simplified vector in component form is: \[ 10\vec{i} + 0\vec{j} = 10\vec{i} \]
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