3 L contaminated air 50 mL 0.0116 M in an air pollution analysis Carbon dioxide (CO2) BaCO3 is passed through Ba (OH) 2 solution. is precipitated as. Excess of base, next to phenol phthalate (f.f.) indicator It is titrated with 23.6 mL of 0.0108 M HCl. CO2 in this air sample Calculate its concentration in ppm. (Density of CO2 Take it as 1.98 g / L. C = 12, O = 16 g / mol).
3 L contaminated air 50 mL 0.0116 M in an air pollution analysis Carbon dioxide (CO2) BaCO3 is passed through Ba (OH) 2 solution. is precipitated as. Excess of base, next to phenol phthalate (f.f.) indicator It is titrated with 23.6 mL of 0.0108 M HCl. CO2 in this air sample Calculate its concentration in ppm. (Density of CO2 Take it as 1.98 g / L. C = 12, O = 16 g / mol).
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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3 L contaminated air 50 mL 0.0116 M in an air pollution analysis
Carbon dioxide (CO2) BaCO3 is passed through Ba (OH) 2 solution.
is precipitated as. Excess of base, next to phenol phthalate (f.f.) indicator
It is titrated with 23.6 mL of 0.0108 M HCl. CO2 in this air sample
Calculate its concentration in ppm. (Density of CO2
Take it as 1.98 g / L. C = 12, O = 16 g / mol).
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