3- If AX=(BA78). Write a program that finds the value of AX after executing each instruction in figure 6-3. suppose count-3. write the results as shown below: AX=(BA78). Count=3 Inst. Result ROL ROR RCL RCR Figure 6-3
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- Implement the counter increment, and branch back to the start of the loop. When you havecompleted these steps, the basic structure of the counter control loop has been implemented,and your code should look similar to the following:.text li $s0, 0 lw $s1, n start_loop: sle $t1, $s0, $s1 beqz $t1, end_loop # code block addi $s0, $s0, 1 b start_loop end_loop:.data n: .word 5please use python language instruction- 1. Read the code from line 123 to line 137. This is the basically the selection. Remember how we talk about there are certain things about controlling population? Please explain how we make sure that the population, when going through a selection, does not shrink over generation. You may simply explain this as comments in a Python file as opposed to in a Word file:. Note that the code from line 123 to line 137 is divided into two small blocks. Use that as 2. The code we've just examined has one functionality of selection. So, we really should wrap that into one function nanied 'select'. Note that in this file there is no class named 'Population'. So, you should make this function a static method that belongs to the class named 'Individual', or a simple function that resides outside the class named 'Individual'. Please think about what the inputs and output of this function are before you start coding. Once you have created the…SPIM simulator (QtSpim). Simulation: Write a MIPS program that computes the expression; y = A * B + C * D Where A, B, C, and D are integers
- Assignment for Computer Architecture Instructions: The assignment is to create a program that adds the number 1/2 to itself a large number of times and adds the number 1/3 to itself a large number of times separately first using type float and then type double. It is to then compare the values of adding the numbers to multiplying 1/2 time the number of times added to compute the “same sum” in a different way. The program will also multiply 1/3 times the number of times 1/3 was added to itself to compute the “same sum” in a different way. The program will then compare these two methods at arrive for the same value and output the difference. Hint, the value for the ½’s will be the same for the smaller numbers of times, the 1/3’s will never be the same. The output from your program is to be to a *.txt file which you are to turn in along with your code. The program must first add the ½’s and 1/3’s using type float and compare to the value obtain using multiplication instead of addition.…Below C-code has a for loop which will repeat 1000 times of the operation. This code will be running on very simple machine. Change the code to reduce the number of branch instructions. You can have up to 5 lines (statements) within the for loop. What is the number of branch operations before and after? for (i=0; i<1000; i++){ y[i] = w * x[i] + b[i]; }Note: assembly language(8086 microprocessor) Write a program that takes a number N (2 digit decimal) as input. Then the user will enter that many numeric values ranging from 0 to 9 as input. Here the user may enter a negative number too. The program then finds a pair of values whose summation is closest to zero.Explanation: Here at first the user enters 10, which is a 2 digit decimal number. That means the user now has to enter 10 negative or positive digits ranging from 0 to 9. Then the program will calculate the sum of all possible pairs and find the pair which gives the minimum sum. Here from the given example, we see that the sum of -2 and -4 which is -6 is the least sum.Input:10 -2, 3, 7, 4, -4, 7, -8, 0, 9, 9 Output: Pair of values which has the smallest sum = -4, -2
- Assignment for Computer Architecture You are to write a program in MIPS that computes N! using recursion. Remember N! is the product of all the numbers from 1 to N inclusive, that is 1 x 2 x 3 x (N – 1) x N. It is defined as 1 for N = 0 and is undefined for values less than 0. The programs first requests the user to input the value of N (display a prompt first so the user knows what to do). If the input value is less than 0, the program is to display “N! undefined for values less than 0” and then requests the user to input the value of N again. If the value input is non-negative, it is to compute N! using a recursive function, that is one that calls itself. You are to have your name, the assignment number, and a brief description of the program in comments at the top of your program. Since this is an assembly language program, I expect to see comments on almost every line of code in the program. Also make the code neat: line up the command fields, the register fields, and the comment…Write a sequence of statements that display a subroutine’s return address. Hint: the esp register points to the return address stored on the call stack. You can call the procedure WriteHex. This can be solved in 2 lines of code. write a full code in Assembly LanguageHi there, your previous answer to this Q is incomplete/partial. Please first read the instruction carefully and also pey attention to my request. It should be like this: import sys.arg k = str(sys.argv[1])def prRelation(key):if key == 'Darth Vader':print("No, I am your father")else:print("Luke, I am your %s" % (relations[key])) Relation(k)=========================================if sys.argv[1] in relations: ### your code answer ###name = prRelation(str(sys.argv[1]))print("luke, I am your", name)=============================================== Here is my request with full problem instruction. Please answer accordingly. Thanks: I have the working code, but can't find the right code to pass sys arg command line. Main Q: Create a program, luke.py, using the following dictionary: relations = {'Darth Vader':'father', 'Leia':'sister', 'Han':'brother in law', 'R2D2':'droid', 'Rey':'Padawan', 'Tatooine':'homeworld'} The program will take one argument, corresponding…
- Write in assembly language LC3 LC3 simulator to use: https://wchargin.com/lc3web/ Write a program that implements a while loopa. Loop while(R0 > -10)b. For every iteration of the loop subtract 2 from R0c. R0 should start at 0 Use LC3 simulator : https://wchargin.com/lc3web/ Psuedo code: .ORIG x3000 ; NOTE: it says to use R0 for the result; instead, use R3 so the result does not get overwritten when HALT command executes. ; Initialize R3 with #0 ; Set R1 to #10 LOOP ; Decrease R3 by #2 ; Add R1 and R3 and store into R2 ; Branch if positive back to top of loop (we have reached our end condition) DONE ; HALT CPU .ENDwrite in assebly language using lc3 simulator LC3 simulator-https://wchargin.com/lc3web/ Write a program that implements a for loop that adds 5 to R3 every iteration a. Increment a register by 1 in every cycle of the loop to keep track of the loop iterationsb. Store the maximum amount of iterations that the loop can have in a memory locationc. Your for loop should start at 0 iterations (i.e. i = 0) and stop looping once the maximum is reached Psuedo code: .ORIG x3000 ; Step 1: Clear R3 ; Step 2: Clear R0 ; Step 3: Load the value of MAX into R1 (maximum amount of iterations) ; Step 4: Take the two's compliment of R1 (2 instructions!) loop ; Step 5: Add #5 to R3 (result) ; Step 6: Increment R0 (loop iteration counter) ; Step 7: Add R1 and R0 and put the result in R2 (Since we did a 2's complement on R1, we are essentially subtracting R1 from R0) ; Step 8: Branch if negative back to loop (this means that R1 > R0 and we need to keep looping) ; Step 9: Halt CPU…Q: Write an assembly language program that will implement Multiple Choice Question. First of all a message for issuing instructions is to be displayed and in the next line the question is to be printed. Then, in the next line choices are to be printed separated with tabs. Small case letters are to be used to distinguish between different choices. The program has to display 'Correct Answer' message if the correct choice is selected by the user of the program, otherwise 'Wrong Answer' message is to be printed on the monitor screen. Use the MCQ of your own choice.