3) I have just finished running a chlorination reaction (below) using methanol as my solvent. Cl₂ MeOH A CI CI B OMe CI I only expected to see one product - Product A - but somehow, I seem to have generated 2 different products. How could this have happened? Justify the formation of Product B in 1-2 sentences and draw the relevant mechanistic step(s) (2 pts).
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![3) I have just finished running a chlorination reaction (below) using methanol as my solvent.
Cl₂
MeOH
A
CI
CI
B
OMe
CI
I only expected to see one product - Product A - but somehow, I seem to have generated 2
different products. How could this have happened? Justify the formation of Product B in 1-2
sentences and draw the relevant mechanistic step(s) (2 pts).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa2db9e01-afbd-41a4-9efc-e63de16ece79%2F3e8d9b04-c566-4f54-b562-ff638c5a4534%2Fxzm3908_processed.jpeg&w=3840&q=75)
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