3) Given the two-way frequency table below, and one student is chosen, find the probabilities described below. The students at Bertramville High School were surveyed about whether they wanted pizza or burgers at their end-of-year picnic. The data is displayed in the table to the right. と2 burger Total Peshra 121 しりマフフ a) P(pizza and Sophomore) = Suphra 211 189 900 Total 443 777 b) P(pizza or Sophomore) %3D c) P(pizza | Sophomore) = d) P(Freshman U burgers) %3D e) P(Freshman |pizza): %3D f) P(pizza n burgers) = %3D

3) Given the two-way frequency table below, and one student is chosen, find the probabilities described below. The students at Bertramville High School were surveyed about whether they wanted pizza or burgers at their end-of-year picnic. The data is displayed in the table to the right. と2 burger Total Peshra 121 しりマフフ a) P(pizza and Sophomore) = Suphra 211 189 900 Total 443 777 b) P(pizza or Sophomore) %3D c) P(pizza | Sophomore) = d) P(Freshman U burgers) %3D e) P(Freshman |pizza): %3D f) P(pizza n burgers) = %3D

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A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.

Topic Video

Question

own tap shoes
3) Given the two-way frequency table below, and one student is chosen, find the probabilities described
below.
The students at Bertramville High School were surveyed about whether they wanted pizza or burgers
at their end-of-year picnic. The data is displayed in the
table to the right.
PIzza burger
しら|フフ
Total
PRshra
a) P(pizza and Sophomore):
189
Total
443
777
b) P(pizza or Sophomore) =
c) P(pizza | Sophomore) =
d) P(Freshman U burgers) =
%3D
e) P(Freshman | pizza) =
%3D
f) P(pizza n burgers) =

Expert Solution

Step 1

(a)

The data of the survey is given in the problem.

The probability of pizza is,

$P (p i z z a) = \frac{T o t a l n u m b e r o f p i z z a}{n (T)}$

Substitute the values in the above equation.

$\begin{array}{rcl} P (p i z z a) & = & \frac{334}{777} \\ = & 0.43 \end{array}$

The probability of Sophomore is,

$P (s o p h o m o r e) = \frac{T o t a l n u m b e r o f s o p h o m o r e}{n (T)}$

Substitute the values in the above equation.

$\begin{array}{rcl} P (s o p h o m o r e) & = & \frac{400}{777} \\ = & 0.515 \end{array}$

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