**Program Analysis****Program Instructions:**| Address | Instruction ||---------|-------------------|| 100 | Load X || 101 | Store Temp || 102 | JnS Subr | // Store return address, jump to procedure| 103 | Store X || 104 | Load Y || 105 | Store Temp || 106 | JnS Subr | // Store return address, jump to procedure| 107 | Store Y || 108 | Halt || 109 | X, Hex 10 || 10A | Y, Hex 20 || 10B | Z, Hex 30 || 10C | Temp, Hex 0 || 10D | Subr, Hex 0 | // Store return address here| 10E | Load Temp || 10F | Add Temp || 110 | Add Z || 111 | JumpI Subr | // Return to calling code| | END |**Tasks:**- Provide a trace and give the contents (in Hexadecimal number) of PC after execution of each instruction.**Trace Table:**| Instruction | PC ||---------------|-----|| Load X | 101 || Store Temp | 102 || JnS Subr | 10E || Load Temp | 10F || Add Temp | || Add Z | || Halt | 109 |**Value Tracking:**- Determine the values of X, Y, Temp, Subr after running of this program:| Variable | Value (in Hexadecimal) ||----------|------------------------|| X | || Y | || Temp | || Subr | | **Explanation:**- This program loads and stores values using hexadecimal instructions and performs jumps and arithmetic operations. Each step updates specific registers and memory addresses as described.

Name: **Program Analysis****Program Instructions:**| Address | Instruction
Uploaded: 2024-03-20T06:51:23.000Z
Channel: Bartleby
Description: **Program Analysis****Program Instructions:**| Address | Instruction ||---------|-------------------|| 100 | Load X || 101 | Store Temp || 102 | JnS Subr | // Store return address, jump to procedure| 103

Hexadecimal number:- The base value in the hexadecimal number system, which is one sort of number representation, is 16. Thus, there are only 16 symbols or digit values that can be used, including the following ones: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, and F. Where the single-bit representations of the decimal values 10, 11, 12, 13, 14, and 15 are A, B, C, D, E, and F, respectively. Any digit's value can be represented using only 4 bits. An additional 0x prefix or h suffix designates hexadecimal numbers. Solution:- Instruction PC Description Load x 101 load value of x in accumulator so acc=10 Store Temp 102 store value of temp in accumulator so Temp=10 jnS Subr 10E the store return address in Subr=103 Load Temp 10F load the value of temp in acc so acc=10 Add Z 110 add Z so 10+30 in hexadecimal = 40, so acc=40 Jumpi Subr 103 return to Subr= 103 Store X 104 now store the value of acc in X = 40 Load Y 105 load value of Y in acc so acc = 20 Store Temp 106 store value of acc in Temp =20 jnS Subr 10E jump to procedure and store address in Subr=107 Load Temp 10F load value of Temp in acc so acc = 20 Add Z 110 add value with the Z so 20+30 in hexadecimal, acc =50 Jumpi Subr 107 now return to Subr=107 Store Y 108 store value of acc in Y = 50 Halt 109 stop the execution The list with the final value:- Variable Value X 40 Y 50 Temp 20 Subr 107