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(3) given as The pressure difference between two points as measured with a manometer is P2 – P1 = pgh The following figure shows a single U-tube manometer for measuring pressure difference between points “A" and "B". Air Water The U-tube manometer. By determining the pressure at point "a" through the left leg and then through the right leg, show that the difference in pressure between point "A" PA and "B" PB is approximately given by PA - PB = g(h2 - h1)(PH20)

(3) given as The pressure difference between two points as measured with a manometer is P2 – P1 = pgh The following figure shows a single U-tube manometer for measuring pressure difference between points “A" and "B". Air Water The U-tube manometer. By determining the pressure at point "a" through the left leg and then through the right leg, show that the difference in pressure between point "A" PA and "B" PB is approximately given by PA - PB = g(h2 - h1)(PH20)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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(3) given as The pressure difference between two points as measured with a manometer is P2 – P1 = pgh The following figure shows a single U-tube manometer for measuring pressure difference between points “A" and "B". -Air Water The U-tube manometer. By determining the pressure at point “a" through the left leg and then through the right leg, show that the difference in pressure between point "A" Pa and “B' PB is approximately given by Pa – PB = g(h2 – h1)(PH20)
Transcribed Image Text:(3) given as The pressure difference between two points as measured with a manometer is P2 – P1 = pgh The following figure shows a single U-tube manometer for measuring pressure difference between points “A" and "B". -Air Water The U-tube manometer. By determining the pressure at point “a" through the left leg and then through the right leg, show that the difference in pressure between point "A" Pa and “B' PB is approximately given by Pa – PB = g(h2 – h1)(PH20)
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