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(3) For what value of a the vectors: a = 51 +6j-k and b=2i+(3+a)j- ak A. B = AB cos 90º = 0=(51+6j-k). (2 i + (3 + a)j-a k) = 0 = 10 + 18+ 6a+ a=0 = 28+7a=0⇒a= -28 عمودي : are orthogonal

(3) For what value of a the vectors: a = 51 +6j-k and b=2i+(3+a)j- ak A. B = AB cos 90º = 0=(51+6j-k). (2 i + (3 + a)j-a k) = 0 = 10 + 18+ 6a+ a=0 = 28+7a=0⇒a= -28 عمودي : are orthogonal

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(3) For what value of a the vectors: a = 51+6j-k and b=2i+(3+a)j- ak A. B = AB cos 90º =0=(51+6j-k). (21+(3+a)j-ak) = 0 = 10 + 18+ 6a+ a=0 = 28+7α = 0 ⇒a= -4 عمودي : are orthogonal
Transcribed Image Text:(3) For what value of a the vectors: a = 51+6j-k and b=2i+(3+a)j- ak A. B = AB cos 90º =0=(51+6j-k). (21+(3+a)j-ak) = 0 = 10 + 18+ 6a+ a=0 = 28+7α = 0 ⇒a= -4 عمودي : are orthogonal
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