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3 For the circuit above: what is the input equation for KA? A+(x XOR y) AB+ xy B+(x XORY) B(x XNOR y) A+Bx'y` 4 For the circuit above: what is the input equation for JB? АВ Ax'y`+ A'xy ABx+ Bx'y` ABx'y`

3 For the circuit above: what is the input equation for KA? A+(x XOR y) AB+ xy B+(x XORY) B(x XNOR y) A+Bx'y` 4 For the circuit above: what is the input equation for JB? АВ Ax'y`+ A'xy ABx+ Bx'y` ABx'y`

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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For the circuit above: what is the input equation for KA?
3 For the circuit above: what is the input equation for KA? A+(x XOR y) AB+ xy B+(x XORY) B(x XNOR y) A+Bx`y` 4 For the circuit above: what is the input equation for JB? АВху АВ Аху'+ A'ху ABx+ Bx'y ABx'y`
Transcribed Image Text:3 For the circuit above: what is the input equation for KA? A+(x XOR y) AB+ xy B+(x XORY) B(x XNOR y) A+Bx`y` 4 For the circuit above: what is the input equation for JB? АВху АВ Аху'+ A'ху ABx+ Bx'y ABx'y`
1 For the state diagram below state 1 is 00, state 2 is 01, state 3 -10, state 4 -11.Input variables are x and y, output function is z. For the implementation JK flip-flops A(MSB) and B are used. 00/1 10/0 01/0 11/0 W 110 11/0 00/0 0/10 2 3 100 000 11/0 01/0 100 10/0
Transcribed Image Text:1 For the state diagram below state 1 is 00, state 2 is 01, state 3 -10, state 4 -11.Input variables are x and y, output function is z. For the implementation JK flip-flops A(MSB) and B are used. 00/1 10/0 01/0 11/0 W 110 11/0 00/0 0/10 2 3 100 000 11/0 01/0 100 10/0
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