3) Find the Maximum Profit P(x)=? if the price function is p(x) = 20,000 - 50x and the cost function is C'(x) = 5000x + 15,000 Hint: Use Profit = Revenue-Cost ‒‒‒ > P(x)= R(x)- C(x) R(x)=(price) *(quantity)= p*x
3) Find the Maximum Profit P(x)=? if the price function is p(x) = 20,000 - 50x and the cost function is C'(x) = 5000x + 15,000 Hint: Use Profit = Revenue-Cost ‒‒‒ > P(x)= R(x)- C(x) R(x)=(price) *(quantity)= p*x
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
![3) Find the Maximum Profit P(x)=? if the price function is p(x) = 20,000 – 50x
and the cost function is C(x) = 5000x + 15, 000
Hint: Use Profit = Revenue-Cost
P(x)= R(x)- C(x)
R(x)=(price) *(quantity)=_p*x](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9d50ce1e-ee04-4714-a13e-7d98c91332d0%2F65898f94-0fb2-479e-adfc-03e7f374caba%2Fj913a2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3) Find the Maximum Profit P(x)=? if the price function is p(x) = 20,000 – 50x
and the cost function is C(x) = 5000x + 15, 000
Hint: Use Profit = Revenue-Cost
P(x)= R(x)- C(x)
R(x)=(price) *(quantity)=_p*x
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