3) Find the length of the segment. Round to the nearest tenth of a unit. y S(-1, 2) T(3,-2)

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
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### Problem 3: Finding the Length of a Segment

**Question:** 
Find the length of the segment. Round to the nearest tenth of a unit.

**Diagram:**
The diagram provided is a coordinate plane with two points marked:
- Point S is located at (-1, 2).
- Point T is located at (3, -2).

A line segment connects points S and T.

### Explanation:

To find the length of the segment ST, we use the distance formula for two points \((x_1, y_1)\) and \((x_2, y_2)\):

\[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

For points \((x_1, y_1) = (-1, 2)\) and \((x_2, y_2) = (3, -2)\):

1. Substitute the coordinates into the distance formula:
\[ \text{Distance} = \sqrt{(3 - (-1))^2 + (-2 - 2)^2} \]

2. Simplify the expressions inside the square root:
\[ \text{Distance} = \sqrt{(3 + 1)^2 + (-2 - 2)^2} \]
\[ \text{Distance} = \sqrt{(4)^2 + (-4)^2} \]

3. Calculate the squares:
\[ \text{Distance} = \sqrt{16 + 16} \]
\[ \text{Distance} = \sqrt{32} \]

4. Simplify the square root:
\[ \text{Distance} = \sqrt{32} \approx 5.7 \]

### Conclusion:
The length of the segment ST, rounded to the nearest tenth, is approximately **5.7 units**.
Transcribed Image Text:### Problem 3: Finding the Length of a Segment **Question:** Find the length of the segment. Round to the nearest tenth of a unit. **Diagram:** The diagram provided is a coordinate plane with two points marked: - Point S is located at (-1, 2). - Point T is located at (3, -2). A line segment connects points S and T. ### Explanation: To find the length of the segment ST, we use the distance formula for two points \((x_1, y_1)\) and \((x_2, y_2)\): \[ \text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] For points \((x_1, y_1) = (-1, 2)\) and \((x_2, y_2) = (3, -2)\): 1. Substitute the coordinates into the distance formula: \[ \text{Distance} = \sqrt{(3 - (-1))^2 + (-2 - 2)^2} \] 2. Simplify the expressions inside the square root: \[ \text{Distance} = \sqrt{(3 + 1)^2 + (-2 - 2)^2} \] \[ \text{Distance} = \sqrt{(4)^2 + (-4)^2} \] 3. Calculate the squares: \[ \text{Distance} = \sqrt{16 + 16} \] \[ \text{Distance} = \sqrt{32} \] 4. Simplify the square root: \[ \text{Distance} = \sqrt{32} \approx 5.7 \] ### Conclusion: The length of the segment ST, rounded to the nearest tenth, is approximately **5.7 units**.
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