3 Find the area between the curve of X = and the y-axis on the interval [2, 5]. 2.749 3.296 4.159 4.957

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

Find the area between the curve of \( x = \frac{3}{y} \) and the y-axis on the interval \([2, 5]\).

### Diagram Description

The given diagram is a graph illustrating the curve \( x = \frac{3}{y} \), plotted with \( x \)-axis and \( y \)-axis. The curve is approaching the x-axis as \( y \) increases. The area between the curve and the y-axis from \( y = 2 \) to \( y = 5 \) is shaded.

### Multiple Choice Options

1. 2.749
2. 3.296
3. 4.159
4. 4.957

### Solution Explanation

To find the area between the curve and the y-axis, you'll need to integrate the function with respect to \( y \) over the interval \([2, 5]\). The integral to be calculated is:

\[ \text{Area} = \int_{2}^{5} \frac{3}{y} \, dy \]

By solving this integral, you can find the exact value of the area.

---

This format presents the question intuitively and guides the reader through understanding the graph and how to approach solving the problem.
Transcribed Image Text:--- ### Problem Statement Find the area between the curve of \( x = \frac{3}{y} \) and the y-axis on the interval \([2, 5]\). ### Diagram Description The given diagram is a graph illustrating the curve \( x = \frac{3}{y} \), plotted with \( x \)-axis and \( y \)-axis. The curve is approaching the x-axis as \( y \) increases. The area between the curve and the y-axis from \( y = 2 \) to \( y = 5 \) is shaded. ### Multiple Choice Options 1. 2.749 2. 3.296 3. 4.159 4. 4.957 ### Solution Explanation To find the area between the curve and the y-axis, you'll need to integrate the function with respect to \( y \) over the interval \([2, 5]\). The integral to be calculated is: \[ \text{Area} = \int_{2}^{5} \frac{3}{y} \, dy \] By solving this integral, you can find the exact value of the area. --- This format presents the question intuitively and guides the reader through understanding the graph and how to approach solving the problem.
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