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3 fff Sayz dv= - S₁² S₁² ² 8zyz dz dz dy 2

3 fff Sayz dv= - S₁² S₁² ² 8zyz dz dz dy 2

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The image shows a triple integral expression used in calculus to evaluate a function over a three-dimensional region. The expression is as follows: \[ \iiint 8xyz \, dV = \int_{1}^{2} \int_{2}^{3} \int_{0}^{1} 8xyz \, dz \, dx \, dy \] This equation represents the evaluation of the function \(8xyz\) over a defined volume. The integration is performed in the order dz (from 0 to 1), dx (from 2 to 3), and dy (from 1 to 2), indicating the limits for each variable within the nested integrals. This setup is typically used to calculate the volume under the surface defined by the function in three-dimensional space.
Transcribed Image Text:The image shows a triple integral expression used in calculus to evaluate a function over a three-dimensional region. The expression is as follows: \[ \iiint 8xyz \, dV = \int_{1}^{2} \int_{2}^{3} \int_{0}^{1} 8xyz \, dz \, dx \, dy \] This equation represents the evaluation of the function \(8xyz\) over a defined volume. The integration is performed in the order dz (from 0 to 1), dx (from 2 to 3), and dy (from 1 to 2), indicating the limits for each variable within the nested integrals. This setup is typically used to calculate the volume under the surface defined by the function in three-dimensional space.
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