3) Consider the balanced equation: 2 CH3OH (+3 02 (g) → 4 H₂O (g) + 2 CO2 (g) If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO₂, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO₂ = 44.01 gram/mole)
3) Consider the balanced equation: 2 CH3OH (+3 02 (g) → 4 H₂O (g) + 2 CO2 (g) If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO₂, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO₂ = 44.01 gram/mole)
Chemistry
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Chapter1: Chemical Foundations
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Limiting Reactant Practice
If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams of carbon dioxide, CO2, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO2 = 44.01 gram/mole)
4) You performed

Transcribed Image Text:3) Consider the balanced equation: 2 CH3OH (+3 02 (g) → 4 H₂O (g) + 2 CO2 (g)
If you were to burn 20.5 grams of methanol, CH3OH, in 35.6 liters of oxygen gas, O2, at STP, how many grams
of carbon dioxide, CO₂, would be formed? (Molar mass of CH3OH = 32.05 grams/mole, Molar mass of CO₂ =
44.01 gram/mole)
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