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3) Consider a 6-variable Boolean function Лх, хъ, хз, хъ, хs, х6)- fi(x, хъ, хз, х1) . f:(x, xs, х6) where fi(x1, x2, x3, X4) = E(0,4,6,8,9,10,11,13,15) - xı is the most significant bit and f2(x4, x5, x6) = £(0,1,2) - x4 is the most significant bit. Obtain a minimal sum-of-product (SOP) expression for fi and f2 with minimum a) literal counts. b) Obtain a minimal product-of-sum (POS) expression for f with a minimum literal count.

3) Consider a 6-variable Boolean function Лх, хъ, хз, хъ, хs, х6)- fi(x, хъ, хз, х1) . f:(x, xs, х6) where fi(x1, x2, x3, X4) = E(0,4,6,8,9,10,11,13,15) - xı is the most significant bit and f2(x4, x5, x6) = £(0,1,2) - x4 is the most significant bit. Obtain a minimal sum-of-product (SOP) expression for fi and f2 with minimum a) literal counts. b) Obtain a minimal product-of-sum (POS) expression for f with a minimum literal count.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Consider a 6-variable Boolean function
f(x1, x2, x3, x4, x5, x6)= f1(x1, x2, x3, x4) . f2(x4, x5, x6)
where f1(x1, x2, x3, x4) = Σ(0,4,6,8,9,10,11,13,15) - x1 is the most significant bit and
f2(x4, x5, x6) = Σ(0,1,2) - x4 is the most significant bit.
a) Obtain a minimal sum-of-product (SOP) expression for f1 and f2 with minimum literal counts.
b) Obtain a minimal product-of-sum (POS) expression for f with a minimum literal count.

Consider a 6-variable Boolean function 3) Лх, х, хз, х, х5, хө)— fi(x, х, хз, х) . f:(x4, х5, х6) where fi(x1, x2, x3, x4) = E(0,4,6,8,9,10,11,13,15) - xı is the most significant bit and f2(x4, x5, x6) = E(0,1,2) - x4 is the most significant bit. а) literal counts. Obtain a minimal sum-of-product (SOP) expression for fi and f2 with minimum b) Obtain a minimal product-of-sum (POS) expression for f with a minimum literal count.
Transcribed Image Text:Consider a 6-variable Boolean function 3) Лх, х, хз, х, х5, хө)— fi(x, х, хз, х) . f:(x4, х5, х6) where fi(x1, x2, x3, x4) = E(0,4,6,8,9,10,11,13,15) - xı is the most significant bit and f2(x4, x5, x6) = E(0,1,2) - x4 is the most significant bit. а) literal counts. Obtain a minimal sum-of-product (SOP) expression for fi and f2 with minimum b) Obtain a minimal product-of-sum (POS) expression for f with a minimum literal count.
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