3- Complete and balance the following redox equation: H2S + HNO3 --> S + NO (acidic solution)

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**3. Complete and balance the following redox equation:**

\[ \text{H}_2\text{S} + \text{HNO}_3 \rightarrow \text{S} + \text{NO} \]

*(acidic solution)*

---

To balance this redox equation, follow these steps:

1. **Identify the Oxidation and Reduction Half-Reactions:**
   - **Oxidation**: \( \text{H}_2\text{S} \rightarrow \text{S} \)
   - **Reduction**: \( \text{HNO}_3 \rightarrow \text{NO} \)

2. **Balance Each Half-Reaction Separately:**
   - **Oxidation**: 
     \[ \text{H}_2\text{S} \rightarrow \text{S} + 2\text{H}^+ + 2e^- \]
   - **Reduction**: 
     \[ \text{HNO}_3 + 3e^- + 3\text{H}^+ \rightarrow \text{NO} + 2\text{H}_2\text{O} \]

3. **Equalize Electrons Transferred:**
   - Multiply the oxidation half-reaction by 3 and the reduction half-reaction by 2 to equalize the electrons.

4. **Combine and Simplify:** 
   \[ 3(\text{H}_2\text{S}) + 2(\text{HNO}_3) + 6(\text{H}^+) + 6e^- \rightarrow 3(\text{S}) + 2(\text{NO}) + 4(\text{H}_2\text{O}) + 6(\text{H}^+) + 6e^- \]

5. **Final Balanced Equation:**
   \[ 3\text{H}_2\text{S} + 2\text{HNO}_3 \rightarrow 3\text{S} + 2\text{NO} + 4\text{H}_2\text{O} \]

- **Note**: Make sure to double-check balance of mass and charge. The coefficients ensure that the number of atoms for each element and the charge are the same on both sides of the equation.
Transcribed Image Text:**3. Complete and balance the following redox equation:** \[ \text{H}_2\text{S} + \text{HNO}_3 \rightarrow \text{S} + \text{NO} \] *(acidic solution)* --- To balance this redox equation, follow these steps: 1. **Identify the Oxidation and Reduction Half-Reactions:** - **Oxidation**: \( \text{H}_2\text{S} \rightarrow \text{S} \) - **Reduction**: \( \text{HNO}_3 \rightarrow \text{NO} \) 2. **Balance Each Half-Reaction Separately:** - **Oxidation**: \[ \text{H}_2\text{S} \rightarrow \text{S} + 2\text{H}^+ + 2e^- \] - **Reduction**: \[ \text{HNO}_3 + 3e^- + 3\text{H}^+ \rightarrow \text{NO} + 2\text{H}_2\text{O} \] 3. **Equalize Electrons Transferred:** - Multiply the oxidation half-reaction by 3 and the reduction half-reaction by 2 to equalize the electrons. 4. **Combine and Simplify:** \[ 3(\text{H}_2\text{S}) + 2(\text{HNO}_3) + 6(\text{H}^+) + 6e^- \rightarrow 3(\text{S}) + 2(\text{NO}) + 4(\text{H}_2\text{O}) + 6(\text{H}^+) + 6e^- \] 5. **Final Balanced Equation:** \[ 3\text{H}_2\text{S} + 2\text{HNO}_3 \rightarrow 3\text{S} + 2\text{NO} + 4\text{H}_2\text{O} \] - **Note**: Make sure to double-check balance of mass and charge. The coefficients ensure that the number of atoms for each element and the charge are the same on both sides of the equation.
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