3) By how much would the rate of reaction (see below) change if the concentration of Cl2 increased by a factor of 2.327. The rate law of this reaction is Rate = k[CHCl3][Cl2]1/2. CHCl3(g) + Cl2(g) ↔ CCl4(g) + HCl(g) a) 0.582 times the initial rate           b) 5.415 times the initial rate c) 0.920 times the initial rate d)1.525 times the initial rate

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