3) An analog signal xa(t) = 2*cos(180*pi*t) is sampled at 270HZ. Find:a) The frequency of the analog signalb) The minimum sampling rate for the analog signalc) The discrete-time signal obtained using the Nyquist rated) The discrete-time signal obtained using the given sampling rate.e) Give at least two (2) other signals with frequencies different from the given analogsignal, which when sampled with the given sampling rate, and then the result isconverted back to analog, gives the same original analog signal.Consider the analog signal xa(t) = 3 sin(320 pi*t) - 5 sin(3040 pi*t) + 2 sin(5280 pi*t) – 4sin(8640 pi*t).a) What is the Nyquist rate?b) If sampled at 560HZ, determine the discrete-time signal obtainedc) From the result in (b), determine the analog signal ya(t) derived when subjected to an4)ideal DAC5) An analog signal is defined as xa(t) = 2*exp(-2t)*cos(2pi*3t). Using 10 samples per second with 8levels of quantization:a) Determine the Nyquist rateb) Determine the discrete time signal using the given sampling rate of 10 Hzc) Using Vmax as the initial value of xa(t) and with a dynamic range of 4 volts, compute forthe step size (A)d) Tabulate the values of the discrete-time signal, the quantized discrete-time signal usingrounding-off, the discrete-time signal using truncation, and the respective quantizationerrors for each type of quantization for n=0 to 10.

Given: Note : It is the kind notice that according to the guidelines of the company if the…

Answered: 3) An analog signal xa(t) =…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Problem 1 The Figure below shows a screen shot of a signal recoded by an oscilloscope. a) What are the average and fundamental frequency for the given signal? b) If the signal is sampled with a sampling frequency of 10 Hz, sketch the sampled signal on the same chart. c) Find the average value of the sampled signal. d) Use zero-order hold to convert the sampled signal to a continuous one and sketch your result on the same chart 2. 0.5 0.4 Time (s) 0.1 0.2 0.3 0.6 0.7 0.8 0.9
The output power of filter is 100 mW, when the signal frequency is 5 kHz. When the frequency is increased to 25 kHz, the output power falls to 50 mW. What is the dB change in power ?
For the filter: a) Determine type of filter and the cut-off frequency (Fc). Determine the peak voltage at the cut-off frequency (Fc). b) Find GAIN (Vo/Vi) at f = .1*Fc . Find GAIN (Vo/Vi) at f = 10*Fc . c) Determine the frequency at which GAIN = .4 (i.e., Vo = .4*Vi) . Draw the “Frequency Response Plot” in “Log-Log” format .
B) The following waveform is the RB (return to bios) representation of the serial digital data, find the digital data code and draw the NRZ (non-return to zero) and RZ (return to zero) waveforms. C) The waveform below is the PAM for the analog signal, draw the analog signal, PWM and the PPM for this signal. 12
A central station is setup up for simultaneous monitoring of 10 hospital patients. The data from the 10 patients are brought to a processing center over wires and are sampled, quantized, binary-coded, and time-division-multiplexed. The multiplexed data are transmitted to the monitoring station as shown in the figure below. The bandwidth of the signal received from each patient is 200 Hz. The maximum acceptable error in sample amplitudes is 0.5% of the peak signal amplitude. The sampling rate must be at least twice the Nyquist rate. Determine the sampling rate, the number of levels, the number of bits per level and minimum cable bandwidth needed to transmit the data.
Determine the Nyquist sampling rate and the Nyquist sampling interval for the signals: (b) sinc² (10071) (c) sinc (10071) + sinc (50r t)
7-18 Abasehand signal having components from near de to 8 kHz is used to frequency modulate a high-frequency carrier, and the maximum frequency deviation is set al +12 kHz. Delermine the approximatle transmission bandwidth.
An electronic stethoscope is to be designed to operate within a full frequency range of 20 Hz to 20kHz. The accepted frequency range of human heart sounds is about 20Hz to 200Hz while that of the human lung sounds is about 25Hz to 1500Hz. Design an RC active bandpass filter circuits that could be implemented in a device to process signals that are captured from the heart sounds and the lungs sounds. Assume the voltage signals from the heart sounds from the transducer is 20mV and the desired output voltage is 5V. Use the non-inverting amplifier for your design.
7-22 Abasehand signal with frequency components from near de to 15 kHz frequency modulates a 200-kHz carrier, and the frequency deviation is +3 kHz. The signal is applied as the input to a cascade of two frequency triplers and one frequency doubler. Determine the output (a) center fre- quency, (b) frequency deviation, and (c) deviation ratio.
Draw the spectrum of the sampled signal when the sampling rate is equal to 2.5 × 10* d) Draw the spectrum of the sampled signal when the sampling rate is equal to 1× 104 Draw the spectrum of the sampled signal at the Nyquist rte. An analog signal given by: x() = stn'(104) %3D is sampled using an ideal sampling tchnique. a) What is the Nyquist rate of this signal. Samplesec. the samplekse,
9. PLOT. Plot the sine wave at frequency fm and the sampling signal at frequency fs1. Write a MATLAB program to take input both fm and fs1 and plot the curves mentioned above.,.
5 a) Consider the sample sequence (5000, 5000, 5000, 5000, -5000, -5000, -5000, -5000}. These are samples of a square wave with a period of eight samples or 1ms at 16 KHz sampling frequency. What are the sinusoidal frequencies in the output waveform?

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3) An analog signal xa(t) = 2*cos(180*pi*t) is sampled at 270HZ. Find: a) The frequency of the analog signal b) The minimum sampling rate for the analog signal c) The discrete-time signal obtained using the Nyguist rate

3) An analog signal xa(t) = 2cos(180pi*t) is sampled at 270HZ. Find: a) The frequency of the analog signal b) The minimum sampling rate for the analog signal c) The discrete-time signal obtained using the Nyguist rate