3) A square loop circuit (with a 30.0 V battery, resistance of 6.00 ohms and side length of 2.00 m) is inside a uniform constant B-field as shown. There might be a mistake with the way B is drawn! The force due to the B-field on the circuit current is shown on one of the sides and is given by: F = 12.5NÎ – 12.5NÎ c) You want to induce a current in the circuit to cancel the current created by the battery. You can do this by changing the B-field. dB needed? (also is it positive or negative?) dt What is the rate of change of the B-field

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3) A square loop circuit (with a 30.0 V battery, resistance of 6.00 ohms and
side length of 2.00 m) is inside a uniform constant B-field as shown.
.B
450
There might be a mistake with the way B is drawn!
The force due to the B-field on the circuit current is shown on one of the
sides and is given by: F = 12.5NÎ – 12.5NÎ
c)
You want to induce a current in the circuit to cancel the current created by the battery.
You can do this by changing the B-field.
dB
needed? (also is it positive or negative?)
dt
What is the rate of change of the B-field
Transcribed Image Text:3) A square loop circuit (with a 30.0 V battery, resistance of 6.00 ohms and side length of 2.00 m) is inside a uniform constant B-field as shown. .B 450 There might be a mistake with the way B is drawn! The force due to the B-field on the circuit current is shown on one of the sides and is given by: F = 12.5NÎ – 12.5NÎ c) You want to induce a current in the circuit to cancel the current created by the battery. You can do this by changing the B-field. dB needed? (also is it positive or negative?) dt What is the rate of change of the B-field
Expert Solution
Step 1

The direction of the force in the magnetic field is given by Fleming’s left-hand rule.

Which states that, if the thumb points in direction of force, and the middle finger points toward the current then the index finger will point towards the magnetic field.

So in the given figure, using Fleming’s left hand rule the direction of the magnetic field points outward the plane of the paper.

Therefore, in the given problem the direction of the magnetic field is wrong, it must be outward the plane of the paper.

Step 2

(c)

In order to induce a current in the circuit to cancel the current created by the battery, the same amount of emf should be induced in the circuit.

Now from Lenz law, the induced emf be defined as,

ε=-dϕBdtε=-ddtB.Aε=-ddtBAcosθ-dBdt=εA                θ=0°

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