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3) A) select the correct answer:- 1-Inverse z-transform of the system can be calculated using: a) Partial fraction method b) Long division method c) Basic formula of the z-transform d) All of the mentioned

3) A) select the correct answer:- 1-Inverse z-transform of the system can be calculated using: a) Partial fraction method b) Long division method c) Basic formula of the z-transform d) All of the mentioned

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Q3) A) select the correct answer:- 1-Inverse z-transform of the system can be calculated using: a) Partial fraction method b) Long division method c) Basic formula of the z-transform d) All of the mentioned 2- The ZOH is physically equivalent to:- a-D'A b- A/D c- filter 3- For jury stability test and characteristic equation is odd, the condition for stable d- both a and b. system eQ(-1) =0 , bQ(-IX0, aQ(-1)0 4- steady-state error for type two system and ramp input is equal a) 1 .b) 0.c) infinity , d) there is a value 5-The roots of characteristic equation are z = 0.244 + j0.970 a) System is stable b) system unstable, c) marginally stable Kz B) G(2) = And T-0.5 sec. (z-Xz-0.6065) 1- Find the value of(K) for the steady-state error to a unit-ramp input to be(0.25). 2- For the value of (K) found in part (a), find (C), (Wn) and (time-constant=r) of the system
Transcribed Image Text:Q3) A) select the correct answer:- 1-Inverse z-transform of the system can be calculated using: a) Partial fraction method b) Long division method c) Basic formula of the z-transform d) All of the mentioned 2- The ZOH is physically equivalent to:- a-D'A b- A/D c- filter 3- For jury stability test and characteristic equation is odd, the condition for stable d- both a and b. system eQ(-1) =0 , bQ(-IX0, aQ(-1)0 4- steady-state error for type two system and ramp input is equal a) 1 .b) 0.c) infinity , d) there is a value 5-The roots of characteristic equation are z = 0.244 + j0.970 a) System is stable b) system unstable, c) marginally stable Kz B) G(2) = And T-0.5 sec. (z-Xz-0.6065) 1- Find the value of(K) for the steady-state error to a unit-ramp input to be(0.25). 2- For the value of (K) found in part (a), find (C), (Wn) and (time-constant=r) of the system
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