See Attached (3) A gamma-ray photon with an energy of 1 GeV collides with a stationary proton. The photon scattersbackwards, opposite the direction it had before the collision. The proton scatters in the direction that thephoton had before the collision.(a) What is the energy of the scattered photon?(b) What is the momentum of the scattered photon?(c) What is the kinetic energy of the scattered proton?(d) What is the momentum of the scattered proton?(e) The Sun generates energy because of muclear reactions that occur in its core. A sequence of reactionsthat do this is called the PP I chain (pronounced "p p one chain"). In the PP I chain, four protons fuseinto a helium-4 nucleus and two positrons, since charge is conserved. Also emitted are two neutrinos, sinceangular momentum is conserved. The neutrinos have no charge and negligible mass. Assume all motion inthe PP I chain is non-relativistic, except for the neutrinos. How many MeV of energy does one PP I chaingenerate? Include the energy generated by the positrons annihilating with electrons that must already bein the Sun, since the Sun is electrically neutral. (Look up the masses of a proton, an electron, and ahelium-4 nucleus, which is also called an alpha particle.)

The energy of the photon is 1 GeV, given asE=(pc)2+mo2c4This is the relativistic energy of the photon having momentum pSince the rest mass of photon mo is zero,E=(pc)2E=pcp=E/cp=1GeV/c This is the momentum of the photon having energy 1 GeV The scattering of photon by any charged particle results into compton scattering. The energy of the photon before and after scattering will depend on the angle between the incident photon and the target particle. E'=E1+(Empc2)(1-cosθ)mp is the rest mass of the protonSince, θ=0, cos0=1E'=EE'=1 GeV Since, in this case, the angle between the photon and the proton is 0, the scattered photon energy is equal to the incident photon energy As the energies before and after scattering of the photon are equal, their momentum will also be equal p'=pp'=1 GeV/cFrom the law of conservation of momentum Initial momentum=Final momentumpphoton+pproton=pphoton+pprotonSince, initially the proton was at rest, pproton=0pphoton=pproton-pphotonSince after collision the proton and photon move in opposite directions2pphoton=pprotonpproton=2×1GeV/cpproton=2GeV/c The kinetic energy of the proton is K.Eproton=p22mK.E=(2c)22(0.938GeV/c2)K.E=2.1322 GeV This is the kinetic energy of the scattered protonAnswers: Energy of the scattered photon is 1 GeV Momentum of the scattered photon is 1 GeV/c Kinetic energy of the scattered proton is 2.1322 GeV Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the question and specify the other subparts (up to 3) you’d like answered.

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Advanced Physics

(3) A gamma-ray photon with an energy of 1 GeV collides with a stationary proton. The photon scatters backwards, opposite the direction it had before the collision. The proton scatters in the direction that the photon had before the collision. (a) What is the energy of the scattered photon? (b) What is the momentum of the scattered photon? (c) What is the kinetic energy of the scattered proton?

(3) A gamma-ray photon with an energy of 1 GeV collides with a stationary proton. The photon scatters backwards, opposite the direction it had before the collision. The proton scatters in the direction that the photon had before the collision. (a) What is the energy of the scattered photon? (b) What is the momentum of the scattered photon? (c) What is the kinetic energy of the scattered proton?