3 (a) Express the signal x(t) as a sum of unit step functions for the time interval 3

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Consider the following signal x(t) shown 

**Transcription for Educational Website**

### Problem Description

#### Signal Representation

The figure presents a piecewise function expressed in terms of unit step functions. The signal \( x(t) \) is defined over the time interval \( 3 < t < 6 \).

1. Between \( t = 0 \) and \( t = 3 \), the signal remains at 0.
2. At \( t = 3 \), the signal jumps to a value of 1.
3. Between \( t = 3 \) and \( t = 5 \), the signal remains at 1.
4. At \( t = 5 \), the signal drops to a value of -1.
5. Between \( t = 5 \) and \( t = 6 \), the signal remains at -1.
6. At \( t = 6 \), the signal returns to 0.

#### Task (a)

Express the signal \( x(t) \) as a sum of unit step functions for the time interval \( 3 < t < 6 \).

#### Task (b)

If \( x(t) \) is fed into a Linear Time-Invariant (LTI) system with a step response defined as:
\[ g(t) = e^{-2t} u(t) \]
determine the corresponding output without using convolution.

### Graph Explanation

The graph illustrates the behavior of the signal \( x(t) \):

- **Horizontal Axis (t):** Represents time in seconds (s).
- **Vertical Axis:** Represents the amplitude of the signal, with values ranging from -1 to 1.
- The step changes in the signal can be used to write the signal \( x(t) \) as a sum of shifted unit step functions.

### Approach to Solution

- **Part (a):** Use the information from the graph to express \( x(t) \) as a series involving \( u(t) \), where \( u(t) \) represents the unit step function. The function \( x(t) \) can be expressed based on the changes at \( t = 3, 5, \) and \( 6 \).
- **Part (b):** Employ properties of LTI systems and the step response to find the output, leveraging known transformations without explicitly computing a convolution.
Transcribed Image Text:**Transcription for Educational Website** ### Problem Description #### Signal Representation The figure presents a piecewise function expressed in terms of unit step functions. The signal \( x(t) \) is defined over the time interval \( 3 < t < 6 \). 1. Between \( t = 0 \) and \( t = 3 \), the signal remains at 0. 2. At \( t = 3 \), the signal jumps to a value of 1. 3. Between \( t = 3 \) and \( t = 5 \), the signal remains at 1. 4. At \( t = 5 \), the signal drops to a value of -1. 5. Between \( t = 5 \) and \( t = 6 \), the signal remains at -1. 6. At \( t = 6 \), the signal returns to 0. #### Task (a) Express the signal \( x(t) \) as a sum of unit step functions for the time interval \( 3 < t < 6 \). #### Task (b) If \( x(t) \) is fed into a Linear Time-Invariant (LTI) system with a step response defined as: \[ g(t) = e^{-2t} u(t) \] determine the corresponding output without using convolution. ### Graph Explanation The graph illustrates the behavior of the signal \( x(t) \): - **Horizontal Axis (t):** Represents time in seconds (s). - **Vertical Axis:** Represents the amplitude of the signal, with values ranging from -1 to 1. - The step changes in the signal can be used to write the signal \( x(t) \) as a sum of shifted unit step functions. ### Approach to Solution - **Part (a):** Use the information from the graph to express \( x(t) \) as a series involving \( u(t) \), where \( u(t) \) represents the unit step function. The function \( x(t) \) can be expressed based on the changes at \( t = 3, 5, \) and \( 6 \). - **Part (b):** Employ properties of LTI systems and the step response to find the output, leveraging known transformations without explicitly computing a convolution.
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