(3) a) Establish the relationship between the hazard function h(t) and in- cidence proportion at time t, I(t). An estimated hazard function at time t = 4 is 1.5, interpret it. b) Describe plausible disease scenarios, with the relevant risk intervals, that suggest (i)an increasing hazard function, (ii) a decreasing hazard function.

Q: w + 4 w + 10 6. 8.

A:

Q: Vx +2 = 7

A: We have to find the value of x using given equation

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A:

Q: mn (メハリノ→四 +y²

A:

Q: x² ,2 xp V16-x2

A:

Q: n-6=5

A: Here we have to find the value of n =?  3n-6=5n

Q: 5p2 - p2

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Q: V24x15y5 3

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A: We need to find : ∫1n+1n dn

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A:

Q: 23-8K

A:

Q: Consider F(x) = = F(0) = 0 F'(3) = 6 F'(1) = 0 O F'(4) = 10 F'(2) = 2 I tf(t) tf(t) dt. Which of the…

A:

Q: x+5 in V5 OEX

A:

Q: dv -2 v³ 8.

A: Here I am attaching image so that you understand each and every step.

Q: 3a+4b=5a-t

A: See this solution in below.

Q: 9x+4y=13 3x+5y=9

A:

Q: 9x4 y4  x  x2  y2

A: Given:  9x4y4 × x2y2

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A: We can use normal algebra to solve this problem.

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A: Modulus function always gives positive quantity in result.

Q: x+4y=6,3y=12

A: Given,  x+4y=6 3y=12

Q: 3V3 3.

A:

Q: (v-4)2

A:

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A:

Q: 3+2x2x

A:

Q: a + 4e + 5d+ 3a

A: We will simplify the given expression.     8a+4e+5d+3a=11a+4e+5d

Q: 3x- 13x +4= 0

A:

Q: 4h aー-5

A: We have to find out

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A: this is a two variable linear equation X + 3Y = 9

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A: Here we have to solve , the given differential equation  y"+y'-2y=0 ...........(1)

Q: -3a + 12a

A: -3a+12a=9a

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A: