-3 A curve has for its third derivative equals to x If (1, -1) is a point of inflection of " the curve with a horizontal tangent line, find the equation of the curve. 4y = x² - 4x + 1 4y = 2 ln x + x² − 4x − 1 2y = ln|x| − 2x² 4y = 2 ln|x| + x² + 4x − 9

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A curve has for its third derivative equals to x¯³, If (1, −1) is a point of inflection of
the curve with a horizontal tangent line, find the equation of the curve.
4y = x² - 4x + 1
4y = 2 ln|x| + x²
2y = ln|x| − 2x²
4y = 2ln|x| + x² + 4x − 9
4x 1
-
Transcribed Image Text:A curve has for its third derivative equals to x¯³, If (1, −1) is a point of inflection of the curve with a horizontal tangent line, find the equation of the curve. 4y = x² - 4x + 1 4y = 2 ln|x| + x² 2y = ln|x| − 2x² 4y = 2ln|x| + x² + 4x − 9 4x 1 -
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