**Problem Statement**A bag contains:- 8 red crayons- 14 purple crayons- 6 yellow crayons- 4 green crayons---**WITH REPLACEMENT:**Find the probability of the following events:1. \( \text{P(green then red)} \)2. \( \text{P(two purples)} \)---**WITHOUT REPLACEMENT:**Find the probability of the following events:1. \( \text{P(purple then green)} \)2. \( \text{P(two greens)} \)---Note: "With replacement" means that after drawing one crayon, it is placed back in the bag before drawing the second crayon. "Without replacement" means that the crayon is not returned to the bag after drawing.---**Explanations:**The concepts of "with replacement" and "without replacement" are vital in understanding probability because they affect the number of possible outcomes and the probability of each event occurring in subsequent draws. **With Replacement:**- When you replace the crayon, the total number of crayons remains the same for each draw.- The probability of each individual event is calculated independently.**Without Replacement:**- When you do not replace the crayon, the total number of crayons decreases by one for the subsequent draw.- The probability of the subsequent event is calculated based on the reduced number of crayons available.Understanding these principles helps solve problems that involve calculating probabilities in scenarios where items are drawn from a set, one or more at a time.

Name: **Problem Statement**A bag contains:- 8 red crayons- 14 purple crayon
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Description: **Problem Statement**A bag contains:- 8 red crayons- 14 purple crayons- 6 yellow crayons- 4 green crayons---**WITH REPLACEMENT:**Find the probability of the following events:1. \( \text{P(green then red)} \)2. \( \text{P(two purples)} \)---**WITHOUT

There are total (8+14+6+4)=32 crayons. We can pick any 2 crayon with replacement from 32 crayons in…

Math

Probability

3) A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 green crayons. WITH REPLACEMENT find, P(green then red) P( Two purples) WITHOUT REPLACEMENT find, P(purple tjenn green) P(two greens)

3) A bag contains 8 red crayons, 14 purple crayons, 6 yellow crayons, and 4 green crayons. WITH REPLACEMENT find, P(green then red) P( Two purples) WITHOUT REPLACEMENT find, P(purple tjenn green) P(two greens)

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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