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3) 9 mm Radius = Diameter= Circumference=

3) 9 mm Radius = Diameter= Circumference=

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Example 3: Calculations for a Circle In the diagram provided, there is a circle with a line segment labeled "9 mm" passing through its center. This line segment represents the diameter of the circle. **Given:** - Diameter (d): 9 mm To find the radius (r) of the circle: - The radius is half of the diameter. \[ r = \frac{d}{2} \] \[ r = \frac{9 \text{ mm}}{2} \] \[ r = 4.5 \text{ mm} \] To find the circumference (C) of the circle: - The circumference can be calculated using the formula: \[ C = \pi \times d \] \[ C = \pi \times 9 \text{ mm} \] \[ C \approx 3.14 \times 9 \text{ mm} \] \[ C \approx 28.26 \text{ mm} \] **Summary:** - **Radius (r) = 4.5 mm** - **Diameter (d) = 9 mm** - **Circumference (C) ≈ 28.26 mm**
Transcribed Image Text:### Example 3: Calculations for a Circle In the diagram provided, there is a circle with a line segment labeled "9 mm" passing through its center. This line segment represents the diameter of the circle. **Given:** - Diameter (d): 9 mm To find the radius (r) of the circle: - The radius is half of the diameter. \[ r = \frac{d}{2} \] \[ r = \frac{9 \text{ mm}}{2} \] \[ r = 4.5 \text{ mm} \] To find the circumference (C) of the circle: - The circumference can be calculated using the formula: \[ C = \pi \times d \] \[ C = \pi \times 9 \text{ mm} \] \[ C \approx 3.14 \times 9 \text{ mm} \] \[ C \approx 28.26 \text{ mm} \] **Summary:** - **Radius (r) = 4.5 mm** - **Diameter (d) = 9 mm** - **Circumference (C) ≈ 28.26 mm**
**Problem 4: Calculating Properties of a Circle** **Description:** The image depicts a circle with a diameter labeled as 4.8 cm. Below the circle are several prompts for calculating its various properties. **Diagrams and Explanation:** 1. **Diagram:** - A circle with a diameter of 4.8 cm. **Required Calculations:** 1. **Radius (r):** - The radius is half of the diameter. - Formula: \( r = \frac{D}{2} \) 2. **Diameter (D):** - The diameter of the circle is given. - Value: \( D = 4.8 \) cm 3. **Circumference (C):** - The circumference is the distance around the circle. - Formula: \( C = \pi \times D \) or \( C = 2 \pi r \) 4. **Area (A):** - The area is the space enclosed within the circle. - Formula: \( A = \pi r^2 \) **Prompts for Students:** - **Radius =** - **Diameter = 4.8 cm** - **Circumference =** - **Area =** This setup encourages students to apply the formulas and fill in the missing values based on the given diameter.
Transcribed Image Text:**Problem 4: Calculating Properties of a Circle** **Description:** The image depicts a circle with a diameter labeled as 4.8 cm. Below the circle are several prompts for calculating its various properties. **Diagrams and Explanation:** 1. **Diagram:** - A circle with a diameter of 4.8 cm. **Required Calculations:** 1. **Radius (r):** - The radius is half of the diameter. - Formula: \( r = \frac{D}{2} \) 2. **Diameter (D):** - The diameter of the circle is given. - Value: \( D = 4.8 \) cm 3. **Circumference (C):** - The circumference is the distance around the circle. - Formula: \( C = \pi \times D \) or \( C = 2 \pi r \) 4. **Area (A):** - The area is the space enclosed within the circle. - Formula: \( A = \pi r^2 \) **Prompts for Students:** - **Radius =** - **Diameter = 4.8 cm** - **Circumference =** - **Area =** This setup encourages students to apply the formulas and fill in the missing values based on the given diameter.
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