3-46. In a motion capture study of a runner, one frame shows the subject support- ing her weight on one leg, as shown in Fig. P3.46. The length of the foot Ankle 30° 60° y Knee Toes (a) During a motion capture study. segment (from ankle to toe) is 8 in. and the length of the lower leg (from ankle to knee) is 18 in. (a) Given the angles shown in Fig. P3.46(a), find the position of the knee if the runner's toes touch the ground at the point x = y = 0. (b) Now suppose that the same leg is positioned such that the knee is located in the second quadrant and oriented in the knee-down position (clockwise direction), as shown in Fig. P3.46. If the toes are located at P(x, y) = (-6.25 in., 25 in.), de- termine the values of 0₁ and 02. (-6.25, 25) Knee 0₂ Ankle y, in. Toes 0₁ (b) To find 0₁ and 0₂. x, in.

3-46. In a motion capture study of a runner, one frame shows the subject support- ing her weight on one leg, as shown in Fig. P3.46. The length of the foot Ankle 30° 60° y Knee Toes (a) During a motion capture study. segment (from ankle to toe) is 8 in. and the length of the lower leg (from ankle to knee) is 18 in. (a) Given the angles shown in Fig. P3.46(a), find the position of the knee if the runner's toes touch the ground at the point x = y = 0. (b) Now suppose that the same leg is positioned such that the knee is located in the second quadrant and oriented in the knee-down position (clockwise direction), as shown in Fig. P3.46. If the toes are located at P(x, y) = (-6.25 in., 25 in.), de- termine the values of 0₁ and 02. (-6.25, 25) Knee 0₂ Ankle y, in. Toes 0₁ (b) To find 0₁ and 0₂. x, in.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Related questions

Q: 1 The penny-farthing (aka "Ordinary") is a fixed gear bicycle. If the large wheel has a diameter of…

A: Solution: 1)Given:diameter, d = 70 inchesw, rotational speed = 60 rpm Formula:v = rw where:v =…

Q: A pendulum consisting of three masses is shown below. The middle mass M is fixed at the midpoint of…

A: Given:To find:Equation of motionFrequency of vibration

Q: (3) Use the following graph to answer the questions on this page. The total time is 0.4 seconds.…

A: Solution:

Q: At what distance d, in kilometers, from the surface of the earth on a line fromcenter to center…

Q: A thin hoop of radius R and mass M oscillates in its own vertical plane with one point of the hoop…

Q: A crate of 64 kg simply stands on the moving cart with constant acceleration a. The height from the…

Q: A string holds and wraps around a solid cylinder (7-kg and R = 8-m). A person pulls the string…

Q: A block is being pushed on a flat surface of magnitude 45N. The force of friction on the brick is 13…

Q: A 3-meter-long 25 kg beam is supported by two cables as shown below. You can treat the beam as a…

Q: Draw and discuss the FBD for the following system. • Label all forces and directions. • How many…

A: K

Q: Given: Given: Prior to launch, Balloon tethered by lines AB, AC, and AD. Mass of the balloon is 90…

A: Hi, We can solve only first question for you since the exact one is not specified. Please resubmit…

Q: The plate of a record player with a moment of inertia of 0:015 kg m2 rotates freely at 33 rpm. If…

Q: u =0 UnitsTm/s^ 2 umberT-7.4 7.4 j UnitsTm/s^ 2 umber -0.88 f you would like to Show Work for this…

A: Givenmass of slab m1=40kgmass of block m2=9kgbetween block and slabcoefficient of static friction…

Q: A Lx Find the magnitude of the moment of force F about point A, given: F= Ibs, Lx = 6 ft, Ly = 6…

Q: A particular bicycle has wheels that are 66 cm in diameter. The radius of the crank arm is 18 cm. At…

A: Disclaimer from Bartleby: Since you have posted a question with multiple sub-parts, we will solve…

Q: Suppose you're standing on the ground and throw a frisbee. You want the expression for the…

Q: You are designing a roller coaster ride. The cars (mass m) start from rest at the top (height H) of…

Q: Mechanics question 2: Figure 1.2 shows a ball of mass m = 3 kg, which is released from rest at point…

Q: Question #1: A rigid body is acted upon by the five forces (Newtons) listed below. The position…

Q: Link…

A: Given: Choose an Applied Force at the beginning, and keep it constant for this entire experiment.…

Q: A crate of 69 kg simply stands on the moving cart with constant acceleration a. The height from the…

A: To find: The maximum acceleration of the cart. Given: The mass of the crate is m=69 kg. The…

Q: 4. A skydiver is falling at terminal velocity toward earth moving at 80m/s. The weight of the…

A: Given, Terminal velocity =v = dhdt = 80 m/sWeight of skydriver = W = 800 NEnergy in one gallon of…

Concept explainers

Forming and Shaping

Metal forming is a category of metalworking process through which the material can be given the desired shape and size by subjecting it to plastic deformation, where the component undergoes bulk deformation process upon application of loads. Unlike the shearing and machining process, the material does not undergo up to a failure point as indicated in the stress-strain curve. Hence, the stresses induced during the forming process are greater than yield strength but less than the failure strength of the material. The process does not lead to the loss of material, so it can be said to be an economical process. During forming, the material is subjected to tensile forces, compressive forces, bending, and shearing loading conditions. The material should possess the property of ductility to undergo the forming process.

Question

3.
3-46. In a motion capture study of a runner,
one frame shows the subject support-
ing her weight on one leg, as shown in
Fig. P3.46. The length of the foot
Ankle
30°
60°
. Knee
x
Toes
(a) During a motion capture study.
Figure P3.46 Position of the runner's leg.
segment (from ankle to toe) is 8 in. and
the length of the lower leg (from ankle
to knee) is 18 in.
(a) Given the angles shown in
Fig. P3.46(a), find the position of
the knee if the runner's toes touch
the ground at the point x = y = 0.
(b) Now suppose that the same leg is
positioned such that the knee is
located in the second quadrant and
oriented in the knee-down position
(clockwise direction), as shown in
Fig. P3.46. If the toes are located
at P(x, y) = (-6.25 in., 25 in.), de-
termine the values of 0₁ and 0₂.
(-6.25, 25) Knee
19₂
Ankle
y, in.
Toes
0₁
(b) To find 0₁ and 0₂.
x, in.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1: Given

VIEW

Step 2: Calculation of position of knee when toe is at origin

VIEW

Step 3: Calculation of orientation when position of knee is (-6.25 in, 25 in)

VIEW

Solution

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 16 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Similar questions

Physics 121 Spring 2021 - Document #11: Homework #04 & Reading Assignment page 4 of 8 Problem 1: Gnome Ride - This from a Previous Exam I. A Gnome of given mass M goes on the Gnome Ride as follows: He stands on a horizontal platform that is connected to a large piston so that the platform is driven vertically with a position as a function of time according to the following equation: y(t) = C cos(wt) Here w is a constant given angular frequency, C is a given constant (with appropriate physical units) and y represents the vertical position, positive upward as indicated. Part (a) - What is the velocity of the Gnome at time t = 0? Explain your work. Present your answer in terms of the given parameters Part (b) – What is the net force on the Gnome at time t = 0? Explain your work. Present your answer in terms of the given parameters Part (c) – What is the Normal Force on the Gnome at time t = 0? Explain your work. Present your answer in terms of the given parameters Some Possibly Useful…
Dynamics problem
Ignore the "see figure" part! thank you for all your help
(Scale: 45 m @ 60° Northwest 18 m 24 m East 34 m North 2. A car is driven 220 km East and then 80 km @ 30° Northeast. What is the displacement of the car from the point of origin? (Scale: 1 cm = 20 km Use Tip-to-Tail Method) 1050 N act at the same point of an object and make West while the 250 N acts Force 10 N Southeast Scale
A crate of 67 kg simply stands on the moving cart with constant acceleration a. The height from the center of gravity to the cart, L, is 1.2 m, and the angle = 12°. What is the maximum acceleration a (in m/s²) the cart can have without tipping over on the cart? The coefficient of static friction between the crate and the cart is μg = 0.55. Please pay attention: the numbers may change since they are randomized. Your answer must include 3 places after the decimal point. Take g = 9.81 m/s². 0.5 m 0.5 m L Your Answer: ● 0 Answer G
Hello. Answer is s=0.42m (how far the spring goes down before stopping the object falling). I am uploading this question as the example answer's working out was bad I find it hard to follow. I would like to see working out how the calculations equate to the answer being s=0.42m
Don't Use Chat GPT Will Upvote And Give Handwritten Solution Please
In a nutshell, a smaller rock is propelled into the air as a huge counterweight in the back falls down, effectively converting gravitational potential energy into kinetic energy for the rock and the weight. But, since the rock is smaller.. it is propelled at a much faster velocity! Let's say we wanted to hurl a 50 kg boulder at a castle wall 100 meters away. Our wooden structure for the trebuchet is 10 meters tall, so that is the maximum distance the counterweight can fall. Assuming the launch angle is a perfect 45 degrees, and the boulder is released from ground level, derive the needed mass of the counterweight that will give the boulder enough kinetic energy to reach the base of the castle walls. You may assume no energy is "lost" due to friction, and ALL the counterweight's gravitational potential energy is converted into the boulder's kinetic enerqy. (HINT: You will need to employ 2D kinematics to find the needed final velocity, then use that final velocity in an energy equation…
4. A rod of length L, = 1.50 m moves along the horizontal direction. The rod makes an angle 0, = 25.0° with the x' axis of its own moving reference frame S'. (a) How fast will the rod need to be traveling relative to an observer at rest to measure and angle of e = 71.0° with the axis x of the rest reference frame S? (b) If the rod has a mass of 1.00 kg, then how much work would have been done to accelerate the rod to this speed from an initial speed of 1.00 x 105 m/s?
A professor's office door is 0.99 m wide, 2.2 m high, 4.2 cm thick; has a mass of 27 kg, and pivots on frictionless hinges. A "door closer" is attached to door and the top of the door frame. When the door is open and at rest, the door closer exerts a torque of 5.6 N*m. What is the moment of inertia of the door? If you let go of the open door, what is its angular acceleration immediately afterward?