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3 3 tan (80) – tan °(80) Establish the identity. tan (240) = %3D 2 1-3 tan (80) Choose the sequence of steps below that verifies the identity. O A. 2 tan (80) + tan (80) tan (160) + tan (80) 2 1- tan (80) 3 3 tan (80) – tan (80) tan (160 + 80) = 2 tan (80) 1- tan (160) tan (80) 1- tan (80) 1-3 tan 2 (80) 1- tan (80) В. 2 tan (160) tan (80) tan (320) + tan (80) 1- tan (160) 3 tan (80) – tan °(80) tan (320 – 80) 2 tan (160) 1+ 2 1- tan (160) 1- tan (320) tan (80) tan (80) 1-3 tan 2 (80) OC. 2 tan (80) tan (80) tan (160) – tan (80) 1+ tan (80) 3 3 tan (80) – tan (80) tan (160 + 80) = 2 tan (80) 1+ 1+ tan (80) 1+ tan (160) tan (80) tan (80) 1-3 tan 2 (80)

3 3 tan (80) – tan °(80) Establish the identity. tan (240) = %3D 2 1-3 tan (80) Choose the sequence of steps below that verifies the identity. O A. 2 tan (80) + tan (80) tan (160) + tan (80) 2 1- tan (80) 3 3 tan (80) – tan (80) tan (160 + 80) = 2 tan (80) 1- tan (160) tan (80) 1- tan (80) 1-3 tan 2 (80) 1- tan (80) В. 2 tan (160) tan (80) tan (320) + tan (80) 1- tan (160) 3 tan (80) – tan °(80) tan (320 – 80) 2 tan (160) 1+ 2 1- tan (160) 1- tan (320) tan (80) tan (80) 1-3 tan 2 (80) OC. 2 tan (80) tan (80) tan (160) – tan (80) 1+ tan (80) 3 3 tan (80) – tan (80) tan (160 + 80) = 2 tan (80) 1+ 1+ tan (80) 1+ tan (160) tan (80) tan (80) 1-3 tan 2 (80)

Trigonometry (11th Edition)
Trigonometry (11th Edition)
11th Edition
ISBN:9780134217437
Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels
Chapter1: Trigonometric Functions
Section: Chapter Questions
Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.
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3 3 tan (80) – tan °(80) Establish the identity. tan (240) = 1-3 tan (80) Choose the sequence of steps below that verifies the identity. O A. 2 tan (80) + tan (80) 3 tan (160) + tan (80) 2 1- tan (80) 3 tan (80) – tan (80) tan (160 + 80) : %3D 2 tan (80) 1- tan (160) tan (80) tan (80) 1-3 tan? (80) 1 1- tan (80) В. 2 tan (160) - tan (80) tan (320) + tan (80) 2 1- tan (160) 3 tan (80) – tan (80) tan (320 – 80) = 1- tan (320) tan (80) 2 tan (160) 1+ tan (80) 1-3 tan an² (80) 1- tan(160) OC. 2 tan (80) tan (80) tan (160) – tan (80) 2 1+ tan (80) 3 tan (80) – tan (80) tan (160 + 80): %3D 2 tan (80) 1+ tan (160) tan (80) tan (80) 1-3 tan? (80) 1+ 1+ tan (80)
Transcribed Image Text:3 3 tan (80) – tan °(80) Establish the identity. tan (240) = 1-3 tan (80) Choose the sequence of steps below that verifies the identity. O A. 2 tan (80) + tan (80) 3 tan (160) + tan (80) 2 1- tan (80) 3 tan (80) – tan (80) tan (160 + 80) : %3D 2 tan (80) 1- tan (160) tan (80) tan (80) 1-3 tan? (80) 1 1- tan (80) В. 2 tan (160) - tan (80) tan (320) + tan (80) 2 1- tan (160) 3 tan (80) – tan (80) tan (320 – 80) = 1- tan (320) tan (80) 2 tan (160) 1+ tan (80) 1-3 tan an² (80) 1- tan(160) OC. 2 tan (80) tan (80) tan (160) – tan (80) 2 1+ tan (80) 3 tan (80) – tan (80) tan (160 + 80): %3D 2 tan (80) 1+ tan (160) tan (80) tan (80) 1-3 tan? (80) 1+ 1+ tan (80)
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