3 3 tan (80) – tan °(80) Establish the identity. tan (240) = %3D 2 1-3 tan (80) Choose the sequence of steps below that verifies the identity. O A. 2 tan (80) + tan (80) tan (160) + tan (80) 2 1- tan (80) 3 3 tan (80) – tan (80) tan (160 + 80) = 2 tan (80) 1- tan (160) tan (80) 1- tan (80) 1-3 tan 2 (80) 1- tan (80) В. 2 tan (160) tan (80) tan (320) + tan (80) 1- tan (160) 3 tan (80) – tan °(80) tan (320 – 80) 2 tan (160) 1+ 2 1- tan (160) 1- tan (320) tan (80) tan (80) 1-3 tan 2 (80) OC. 2 tan (80) tan (80) tan (160) – tan (80) 1+ tan (80) 3 3 tan (80) – tan (80) tan (160 + 80) = 2 tan (80) 1+ 1+ tan (80) 1+ tan (160) tan (80) tan (80) 1-3 tan 2 (80)

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