3-16. Find the absolute and percent relative uncertainty, and express each answer with a reasonable number of significant figures. a. 9.23 (+0.03) mL+4.21 (+0.02) mL-3.26 (+0.06) ml=?9.23 (±0.03) mL + 4.21 (±0.02) mL - 3.26 (±0.06) mL = ? b. 91.3 (±1.0) mM×[40.3 (+0.2) mL]+[21.1 (±0.2) mL]=?91.3 (±1.0) mM x [40.3 (±0.2) mL] ÷ [21.1 (±0.2) mL] = ? c. [4.97 (±0.05) mmol-1.86 (±0.01) mmol]+[21.1 (±0.2) mL]=? [4.97 (±0.05) mmol - 1.86 (±0.01) mmol] [21.1 (±0.2) mL] =? 120011214 61 +0.01 ) —?
3-16. Find the absolute and percent relative uncertainty, and express each answer with a reasonable number of significant figures. a. 9.23 (+0.03) mL+4.21 (+0.02) mL-3.26 (+0.06) ml=?9.23 (±0.03) mL + 4.21 (±0.02) mL - 3.26 (±0.06) mL = ? b. 91.3 (±1.0) mM×[40.3 (+0.2) mL]+[21.1 (±0.2) mL]=?91.3 (±1.0) mM x [40.3 (±0.2) mL] ÷ [21.1 (±0.2) mL] = ? c. [4.97 (±0.05) mmol-1.86 (±0.01) mmol]+[21.1 (±0.2) mL]=? [4.97 (±0.05) mmol - 1.86 (±0.01) mmol] [21.1 (±0.2) mL] =? 120011214 61 +0.01 ) —?
Chapter5: Errors In Chemical Analyses
Section: Chapter Questions
Problem 5.9QAP
Question
Show work. don't give Ai generated solution
![3-16. Find the absolute and percent relative uncertainty, and express each answer with a reasonable number of significant
figures.
a. 9.23 (+0.03) mL+4.21 (+0.02) mL-3.26 (+0.06) ml=?9.23 (±0.03) mL + 4.21 (±0.02) mL - 3.26 (±0.06) mL = ?
b. 91.3 (±1.0) mM×[40.3 (+0.2) mL]+[21.1 (±0.2) mL]=?91.3 (±1.0) mM x [40.3 (±0.2) mL] ÷ [21.1 (±0.2) mL] = ?
c. [4.97 (±0.05) mmol-1.86 (±0.01) mmol]+[21.1 (±0.2) mL]=?
[4.97 (±0.05) mmol - 1.86 (±0.01) mmol] [21.1 (±0.2) mL] =?
120011214 61 +0.01 ) —?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F72b71439-7c40-4452-9e3f-9e2bbdd8e372%2Fde0948b8-e5ef-47e3-b2cb-f8c890abfac3%2Fb1x0oe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3-16. Find the absolute and percent relative uncertainty, and express each answer with a reasonable number of significant
figures.
a. 9.23 (+0.03) mL+4.21 (+0.02) mL-3.26 (+0.06) ml=?9.23 (±0.03) mL + 4.21 (±0.02) mL - 3.26 (±0.06) mL = ?
b. 91.3 (±1.0) mM×[40.3 (+0.2) mL]+[21.1 (±0.2) mL]=?91.3 (±1.0) mM x [40.3 (±0.2) mL] ÷ [21.1 (±0.2) mL] = ?
c. [4.97 (±0.05) mmol-1.86 (±0.01) mmol]+[21.1 (±0.2) mL]=?
[4.97 (±0.05) mmol - 1.86 (±0.01) mmol] [21.1 (±0.2) mL] =?
120011214 61 +0.01 ) —?
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