3-16. Find the absolute and percent relative uncertainty, and express each answer with a reasonable number of significant figures. a. 9.23 (+0.03) mL+4.21 (+0.02) mL-3.26 (+0.06) ml=?9.23 (±0.03) mL + 4.21 (±0.02) mL - 3.26 (±0.06) mL = ? b. 91.3 (±1.0) mM×[40.3 (+0.2) mL]+[21.1 (±0.2) mL]=?91.3 (±1.0) mM x [40.3 (±0.2) mL] ÷ [21.1 (±0.2) mL] = ? c. [4.97 (±0.05) mmol-1.86 (±0.01) mmol]+[21.1 (±0.2) mL]=? [4.97 (±0.05) mmol - 1.86 (±0.01) mmol] [21.1 (±0.2) mL] =? 120011214 61 +0.01 ) —?

Fundamentals Of Analytical Chemistry
9th Edition
ISBN:9781285640686
Author:Skoog
Publisher:Skoog
Chapter5: Errors In Chemical Analyses
Section: Chapter Questions
Problem 5.9QAP
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3-16. Find the absolute and percent relative uncertainty, and express each answer with a reasonable number of significant
figures.
a. 9.23 (+0.03) mL+4.21 (+0.02) mL-3.26 (+0.06) ml=?9.23 (±0.03) mL + 4.21 (±0.02) mL - 3.26 (±0.06) mL = ?
b. 91.3 (±1.0) mM×[40.3 (+0.2) mL]+[21.1 (±0.2) mL]=?91.3 (±1.0) mM x [40.3 (±0.2) mL] ÷ [21.1 (±0.2) mL] = ?
c. [4.97 (±0.05) mmol-1.86 (±0.01) mmol]+[21.1 (±0.2) mL]=?
[4.97 (±0.05) mmol - 1.86 (±0.01) mmol] [21.1 (±0.2) mL] =?
120011214 61 +0.01 ) —?
Transcribed Image Text:3-16. Find the absolute and percent relative uncertainty, and express each answer with a reasonable number of significant figures. a. 9.23 (+0.03) mL+4.21 (+0.02) mL-3.26 (+0.06) ml=?9.23 (±0.03) mL + 4.21 (±0.02) mL - 3.26 (±0.06) mL = ? b. 91.3 (±1.0) mM×[40.3 (+0.2) mL]+[21.1 (±0.2) mL]=?91.3 (±1.0) mM x [40.3 (±0.2) mL] ÷ [21.1 (±0.2) mL] = ? c. [4.97 (±0.05) mmol-1.86 (±0.01) mmol]+[21.1 (±0.2) mL]=? [4.97 (±0.05) mmol - 1.86 (±0.01) mmol] [21.1 (±0.2) mL] =? 120011214 61 +0.01 ) —?
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