2z I 2 L (2,1, 2) dydadz I = -2/2 8 _z2 D I= f(x,y, z) dydxdz +2 2z-12 8 z2 22 2 • 2/2 8 z2 I = f(x, y, z) dydxdz+ f(x, y, z) dydxdz 2z Jo 22 8 z22 2 I = f(x, y, z) dydxdz + f(x, y, z) dydxdz 2z 22

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question

Consider the following triple integral

(img3)

Get the dydxdz command

Select one:

(img4)

2
2z-12
I =
f(r, Y, z) dydædz
2z
2z-12
2
I =
f(x, y, z) dydrdz
2z-y?
/2z-z2
- 2/2
/8 z2
2
8.
I =
f(x, Y, z) dydædz +
f(x, Y, z) dydrdz
2z-12
2
2z-12
2/2
O I=
f(x, y, z) dydædz +
f(x, Y, z) dydxdz
2,
8 z2
2
V2z
2/2
V8
2z-z2
f(2, v, 2) dydzdz + -
I =
f(x, Y, z) dydxdz
8 z2
8 z2_z2
Transcribed Image Text:2 2z-12 I = f(r, Y, z) dydædz 2z 2z-12 2 I = f(x, y, z) dydrdz 2z-y? /2z-z2 - 2/2 /8 z2 2 8. I = f(x, Y, z) dydædz + f(x, Y, z) dydrdz 2z-12 2 2z-12 2/2 O I= f(x, y, z) dydædz + f(x, Y, z) dydxdz 2, 8 z2 2 V2z 2/2 V8 2z-z2 f(2, v, 2) dydzdz + - I = f(x, Y, z) dydxdz 8 z2 8 z2_z2
2
f(x, Y, z) dzdydx
Transcribed Image Text:2 f(x, Y, z) dzdydx
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