2x3y3 + cos(x. y) lim (x.y)-(0,0) (x + 1) 2 sin T +y

Q: 1 |dx I (sec² x csc* x.

A: Integration gives the function whose derivative is given. It is nothing but adding all to make…

Q: f(csc x cot x + 3x2)dx csc x – x3 + c csc x + x3 + c - csc x + x3 +c .3 x° + c O cotx + x3+c

A:

Q: Evaluate fa tan() da 1 글 [(22 + 2a) tan-1 ()-피+C o b을[(22+ 2a) tan-1 () + z] +C 2a) tan-1 ()- 피 +C…

A: Solve the above integration.

Q: cos (2x) dx sinx+cosx COS Evaluate:

A: the given integral is: ∫cos(2x)sinx+cosxdx we have to evaluate the given integral.

Q: y = sin(x + y)

A:

Q: y = arccos /1 – x (1-x) 2 1 (1-x) 2 2 JA (1–x) 2 1 (1–x) 2

A:

Q: x° + x2 + 1 (c) dx. x3 – x2 +2x - 2 arctan x (d) x2

A:

Q: sinx

A:

Q: Vx+1- /2x x² - x 2х f ) lim x→1

A: As per our guidelines we are suppose to solve only first question. Kindly repost the other question…

Q: 7/4 (sec² x – sin x)dx

A: 1. ∫sec2x dx=tanx 2. ∫sinx dx=-cosx 3.∫(u±v)dx=∫u dx±∫v dx 4. ∫abf(x) dx=F(b)-F(a), where ∫f(x)…

Q: S sec² (7t) tan² (7t) √1 – tan² (7t) dt

A: Given integral:- ∫sec27ttan27t1-tan27tdt

Q: sec(2) tan(2) – 1 dz 3.

A:

Q: Find a suitable substitution for evaluating ∫tan x sec2 x dx andexplain your choice.

A: we have to integrate the following integral using a suitable substitution. ∫tanx.sec2xdx

Q: 4x 3-limx-0 tan5x sin(cos y) 4-lim, y- 2

A:

Q: y-Castesinz şinz

A: The detailed solution is as follows below:

Q: dx x√3x² + 2x - 1 - arcsin 1-x 2x +C (Hint: Let x = 1/z.)

A:

Q: sec2 x tan ydx + sec² y tan xdy = 0.

A:

Q: 9. sec(1- x) tan(1 – x) dx

A:

Q: sec² (x) tan° (x)dx

A:

Q: f Lan 2X e *3 of +sec2X Pinel dy o

A:

Q: y = Secx ( sinx+ Cosx)

A: Given, y=secxsinx+cosx And we have to find the dydx.

Limits

When it comes to calculus, limits are considered to be a very important topic of discussion. The main importance of limit lies in expressing the value of a function as it gets closer to a certain value. Also, limits can help you to understand other topics, such as continuity and differentiability better. In a broader sense, every calculus notion is a limit. Other branches of calculus have also been derived from limits.