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2x2 Using the second derivative test for critical points of the function y = –x' 3 16x, which of the following statements is + true? A At x = 2, y" is positive, concave downwards, hence y(2) is a relative maximum value. At x = -4, y" is negative, concave downwards, hence y(-4) is a relative maximum value. At x = 2, y" is positive, concave upwards, hence y(2) is a relative maximum value. At x = -4, y" is negative, concave downwards, hence y(-4) is a relative minimum value.

2x2 Using the second derivative test for critical points of the function y = –x' 3 16x, which of the following statements is + true? A At x = 2, y" is positive, concave downwards, hence y(2) is a relative maximum value. At x = -4, y" is negative, concave downwards, hence y(-4) is a relative maximum value. At x = 2, y" is positive, concave upwards, hence y(2) is a relative maximum value. At x = -4, y" is negative, concave downwards, hence y(-4) is a relative minimum value.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Using the second derivative test for critical points of the function y = -x' + 2x² - 16x, which of the following statements is 3 true? A) At x = 2, y" is positive, concave downwards, hence y(2) is a relative maximum value. В At x = -4, y" is negative, concave downwards, hence y(-4) is a relative maximum value. c) At x = 2, y" is positive, concave upwards, hence y(2) is a relative maximum value. At x = -4, y" is negative, concave downwards, hence y(-4) is a relative minimum value. Ouectien
Transcribed Image Text:Using the second derivative test for critical points of the function y = -x' + 2x² - 16x, which of the following statements is 3 true? A) At x = 2, y" is positive, concave downwards, hence y(2) is a relative maximum value. В At x = -4, y" is negative, concave downwards, hence y(-4) is a relative maximum value. c) At x = 2, y" is positive, concave upwards, hence y(2) is a relative maximum value. At x = -4, y" is negative, concave downwards, hence y(-4) is a relative minimum value. Ouectien
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