2x2 + 3x – 3 dx X - 9

Q: (8x³ - 15x2 + 9) dx

A:

Q: 3 2x dx 2? - 4х + 5 C. 2)

A:

Q: 4x + 3 5+4x - x² dx

A:

Q: 5**+2x (2x3 +1)dx *(2x3+1)dx

A: Use the following formulas 1.∫ axln xdx=axln a+c2. ddxxn=nxn-1

Q: . 2x² – 7x – 5 7х—5 dx 2x+1

A: We need to evaluate ∫2x2-7x-52x+1dx Consider ∫2x2-7x-52x+1dx = ∫2x2+(x-8x)-52x+1dx=…

Q: x5 + 1 dx x4 + 2x3

A:

Q: 2x – x + 4 dx x3 + 4x

A:

Q: 3x + 10 dx x² + 2x + 5

A:

Q: 2x3 dx 2x2-4x+3 3.

A:

Q: 5x2-12 х-12 dx х3-4х

A: Given: ∫5x2-2x-12x3-4x

Q: J 3x - 2 4x² + 4x + 17 dr

A: Breaking the numerator is the key here. After that, break the given function into two parts and then…

Q: (4x + 5) dx 3. (2 - 7х)2

A: Consider the given integration as ∫4x+52-7x2dx

Q: dx Vx -9

A:

Q: 2x3 – 9x2 + 11 dx x2 – 4x + 1

A: We know, ∫dxx=lnx ∫xndx=xn+1n+1 for any real number n.

Q: Suaef(Ox-tan(Sx-) dx 2 2

A: Given:

Q: ,3 dx 3 Vx²-16

A: Given integral I=∫x3x2-163 dx

Q: x3 dx J4- x4

A: ∫x3dx4-9x4Multiply & divide by -36 =-136∫-36x3dx4-9x4since, ∫f'(x)f(x)dx= 2f(x)

Q: 2x + 3 dx 4x2 – 4x + 5

A: The objective of the question is evaluate the indefinite integral.

Q: O/ Eve luate the fo llowing x² V 4 -9x² dx (2) x²-4X+13

A:

Q: бх + 20 4. 522 — dx 186х — 8

A: This can be solved easily by integrating properly and expanding the terms.

Q: x4 + 12x² + 1 dx x5 + 20x³ + 5x

A: Integration is given,

Q: SX³V1+ 4x2 dx .3

A:

Q: se-2+10 dx V4e

A:

Q: 2vx2 2 dx

A:

Q: 1 -dx 8х — 24

A: ∫18x-24dx

Q: • S (++:) (- 1 x2 – 1 dx - x2

A:

Q: 2x+3 (2x² + 6x - 1)5 S 1)5 dx

A:

Q: 3x² + 2x t 3 dx と 20

A:

Q: 2 S. x*- 4x +4 dx (メ-2)(x4) |

A: Solution: Consider the given integral is: I = ∫x2-4x+4(x-2)(x2+4)dxI = ∫x-22(x-2)(x2+4)dxI =…

Q: 3x-6 dx VE-2

A:

Q: x* +3 +00 -dx x2 + 3x +1

A: first we solve for indefinite integral…

Q: + C 2x dx

A:

Q: (4x² + 3x² + 2x + 5)dx

A: we have to find the given integral.∫4x3+3x2+2x+5dx

Q: S x²(In x)²dx

A: We can solve the integration as below using integration by-parts.

Q: S dx 3x-1 b.

A:

Q: 10x3 dx 1+ x³

A: Given ∫10x31+x3dx

Power Operation

Power operation is topic of algebra in Math. It is use to represent repeated multiplication. Very big number and very small number can be easily express using power operation. Power operation is useful in many fields. In space engineering, it helps in representing the distance or size of particular heavenly body. In medical field, it is used to represent very small size. In medical field it helps to mention size of bacteria or virus. 

Exponents

The exponent or power or index of a variable/number is the number of times that variable/number is multiplied by itself.