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2x1 - 6х2 — х3 %3D —38 x3 = -38 — 3x1 — х2 + 7х3 — — 34 —8x1 + х2 — 2х3 %3 — 20

2x1 - 6х2 — х3 %3D —38 x3 = -38 — 3x1 — х2 + 7х3 — — 34 —8x1 + х2 — 2х3 %3 — 20

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Using Gauss Jacobi method on obtaining the linear equation. corresponding table with graph and 4 decimal places. 

2x1 - 6х2 — х3 %3D —38 x3 = -38 — 3x1 — х2 + 7х3 — — 34 —8x1 + х2 — 2х3 %3 — 20
Transcribed Image Text:2x1 - 6х2 — х3 %3D —38 x3 = -38 — 3x1 — х2 + 7х3 — — 34 —8x1 + х2 — 2х3 %3 — 20
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