2x" /(x+1)} You found that the reduction formula of a certain integral is I, = 2n In-1 2n+3 and that 2n+3 2 Io = V(x + 1)*. What is I2? O 2 8 xV(x+ 1)³ 35 1}* – 16 V(x + 1)³ 105 O 2 8. xV(x + 1}* + 16 (x + 1)³ 105 35*V(x + 1)3 O 2 xVx + 1)* 16 *V(x + 1)* + V(x + 1)³ 105 35 Vx + 1)° + 3*V O 2 8 x/(x+1)³ + 16 Vx + 1) 105

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