Please help solve, thank you. Let H={ ;]*•*^^}{]: 2x² + 8y² ≤1a subspace of R².which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is notH is not a subspace of R2 because the two vectors1√√20(Use a comma to separate vectors as needed.)H is not a subspace of R2 because the scalar 2 and the vector√8show that H is not closed under addition.show that H is not closed under scalar multiplication.

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[] : 2x² +8y² ≤1 which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not a subspace of R². Let H= H is not a subspace of R2 because the two vectors √2 0 (Use a comma to separate vectors as needed.) H is not a subspace of R2 because the scalar 2 and the vector 0 1 √8 show that H is not closed under addition. show that H is not closed under scalar multiplication.

[] : 2x² +8y² ≤1 which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not a subspace of R². Let H= H is not a subspace of R2 because the two vectors √2 0 (Use a comma to separate vectors as needed.) H is not a subspace of R2 because the scalar 2 and the vector 0 1 √8 show that H is not closed under addition. show that H is not closed under scalar multiplication.

Elementary Linear Algebra (MindTap Course List)

8th Edition

ISBN:9781305658004

Author:Ron Larson

Publisher:Ron Larson

Chapter5: Inner Product Spaces

Section5.CR: Review Exercises

Problem 47CR: Find an orthonormal basis for the subspace of Euclidean 3 space below. W={(x1,x2,x3):x1+x2+x3=0}

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Question

Please help solve, thank you.

Let H=
{ ;]*•*^^}
{]
: 2x² + 8y² ≤1
a subspace of R².
which represents the set of points on and inside an ellipse in the xy-plane. Find two specific examples-two vectors, and a vector and a scalar-to show that H is not
H is not a subspace of R2 because the two vectors
1
√√2
0
(Use a comma to separate vectors as needed.)
H is not a subspace of R2 because the scalar 2 and the vector
√8
show that H is not closed under addition.
show that H is not closed under scalar multiplication.

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