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2x 8. Suppose you wish to apply the FTOLI to the line integral +( where C is the curve parametrized by F(1) = r²î + 21ĵ + (1³ + 1)k for 1st≤3. First assign this vector field to q8vf, then calculate the potential function and assign the result to q8p, lastly subtitute in the end point and start point (calculate these by hand) and subtract, assigning the final result to 98.

2x 8. Suppose you wish to apply the FTOLI to the line integral +( where C is the curve parametrized by F(1) = r²î + 21ĵ + (1³ + 1)k for 1st≤3. First assign this vector field to q8vf, then calculate the potential function and assign the result to q8p, lastly subtitute in the end point and start point (calculate these by hand) and subtract, assigning the final result to 98.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Could I get some help with my MATLAB code?
q8p is correct but q8vf isn't, and i have no idea what to do for q8 itself. This should supposedly be the correct formatting but I'm not 100% sure.

 
figure
[x8, y8, z8] = meshgrid([-5:1:5,-5:1:5,-5:1:5]);
q8vf = quiver3(x8,y8,z8,2.*x8./y8,(1./z8)-(x8.^2./y8.^2),-(y8./z8.^2),0)
syms x y z
q8p=potential([2*x/y,(1/z)-(x^2/y^2),-(y/z^2)],[x,y,z])
2x 8. Suppose you wish to apply the FTOLI to the line integral +( where C is the curve parametrized by F(1) = r²î + 21ĵ + (1³ + 1)k for 1st≤3. First assign this vector field to q8vf, then calculate the potential function and assign the result to q8p, lastly subtitute in the end point and start point (calculate these by hand) and subtract, assigning the final result to 98.
Transcribed Image Text:2x 8. Suppose you wish to apply the FTOLI to the line integral +( where C is the curve parametrized by F(1) = r²î + 21ĵ + (1³ + 1)k for 1st≤3. First assign this vector field to q8vf, then calculate the potential function and assign the result to q8p, lastly subtitute in the end point and start point (calculate these by hand) and subtract, assigning the final result to 98.
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