-2x² + 7x - 8 - (x + 2) (2x - 1) (1 - x) (A) (B (С) (D -dx = -4 ln x + 2 + In|2x - 1| + ln|1 - x| + C 2 ln x + 22 ln |2x - 1|ln|1 - x + C 2 ln x + 22 ln |2x - 1| + In|1 - x + C 2 ln x + 24 ln |2x - 1|ln|1 - x + C
-2x² + 7x - 8 - (x + 2) (2x - 1) (1 - x) (A) (B (С) (D -dx = -4 ln x + 2 + In|2x - 1| + ln|1 - x| + C 2 ln x + 22 ln |2x - 1|ln|1 - x + C 2 ln x + 22 ln |2x - 1| + In|1 - x + C 2 ln x + 24 ln |2x - 1|ln|1 - x + C
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![**Integral Problem**
Evaluate the integral:
\[
\int \frac{-2x^2 + 7x - 8}{(x+2)(2x-1)(1-x)} \, dx
\]
**Answer Choices**
A) \(-4 \ln|x+2| + \ln|2x-1| + \ln|1-x| + C\)
B) \(2 \ln|x+2| - 2 \ln|2x-1| - \ln|1-x| + C\)
C) \(2 \ln|x+2| - 2 \ln|2x-1| + \ln|1-x| + C\)
D) \(2 \ln|x+2| - 4 \ln|2x-1| - \ln|1-x| + C\)
Note: \(C\) represents the constant of integration.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F019fb4ae-aebc-4c9c-a0ae-00e747a06944%2Fd10f4427-0061-4105-94d2-7679841a25fd%2Fhxpffy_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Integral Problem**
Evaluate the integral:
\[
\int \frac{-2x^2 + 7x - 8}{(x+2)(2x-1)(1-x)} \, dx
\]
**Answer Choices**
A) \(-4 \ln|x+2| + \ln|2x-1| + \ln|1-x| + C\)
B) \(2 \ln|x+2| - 2 \ln|2x-1| - \ln|1-x| + C\)
C) \(2 \ln|x+2| - 2 \ln|2x-1| + \ln|1-x| + C\)
D) \(2 \ln|x+2| - 4 \ln|2x-1| - \ln|1-x| + C\)
Note: \(C\) represents the constant of integration.
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