(2x – 5, x 2 0 lim h(x) = x→-4 where h(x) = x + 7, x < 0 Table 1: x -5 -4.5 -4.1 -4.01 -4.001 approaches 4 from the left . lim h(x) %3D X→ー4- (x→ -4) h(x) = x + 7 Table 2: x -3 -3.5 -3.9 -3.99 -3.999 approaches : lim h(x) = X→ー4+ 4 from the h(x) = x + 7 right (x→ -4*)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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lim h(x) =
x--4
(2x – 5, x 2 0
x+7, x < 0
where h(x) =
Table 1: x
-4.5
|-4.1 -4.01 -4. 001
approaches
4 from the left
: lim h(x)
%3D
X→ー4-
(x → -4)
h(x) = x + 7
Table 2: x
-3
|-3.5
|-3.9
-3.99
-3.999
approaches
: lim h(x) =
X--4+
%3D
4 from the
h(x) = x +7
right
(x → -4*)
Transcribed Image Text:lim h(x) = x--4 (2x – 5, x 2 0 x+7, x < 0 where h(x) = Table 1: x -4.5 |-4.1 -4.01 -4. 001 approaches 4 from the left : lim h(x) %3D X→ー4- (x → -4) h(x) = x + 7 Table 2: x -3 |-3.5 |-3.9 -3.99 -3.999 approaches : lim h(x) = X--4+ %3D 4 from the h(x) = x +7 right (x → -4*)
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