2x³ 3x² - 4x + 5 = x-3 solve by long division 1

Q: Solve for x, if ∠1 = (4x+40)   and ∠2 =  (6x-20)

A: Consider

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Q: Solve for x. 2x - 2, x +5

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Q: 3x2 + 5x – 11 = 1

A: Here is the solution:

Q: Solve for x. 2x+29 3x+8

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Q: how do i solve by factoring: 4(x-2)/x-3 +3/x=-3/x(x-3)

A: LCM= x(x-3)We multiply both sides by LCM and distribute it.