2x 20. x -x- 6 4. Solve the inequality:

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
icon
Related questions
Question
Sure! Here is the transcription of the text as it would appear on an educational website:

---

**4. Solve the inequality:**

\[
\frac{2x}{x^2 - x - 6} \geq 0.
\]

**5. Rationalize the numerator:**

\[
\frac{\sqrt{p} + \sqrt{p^2 - 1}}{\sqrt{p} - \sqrt{p^2 - 1}}.
\]

---
Transcribed Image Text:Sure! Here is the transcription of the text as it would appear on an educational website: --- **4. Solve the inequality:** \[ \frac{2x}{x^2 - x - 6} \geq 0. \] **5. Rationalize the numerator:** \[ \frac{\sqrt{p} + \sqrt{p^2 - 1}}{\sqrt{p} - \sqrt{p^2 - 1}}. \] ---
**Point-Slope Form of a Line**

**Problem Statement:**

Find the point-slope form of the line passing through the points \((-3, 4)\) and \( (3, -7) \).

**Solution:**

To find the point-slope form of a line, you need a point on the line and the line's slope. The point-slope form is given by:

\[ y - y_1 = m(x - x_1) \]

where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope. 

1. **Calculate the Slope:**
   The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:
   
   \[
   m = \frac{y_2 - y_1}{x_2 - x_1}
   \]

   Plug in the given points \((-3, 4)\) and \( (3, -7) \):

   \[
   m = \frac{-7 - 4}{3 - (-3)} = \frac{-11}{6}
   \]

2. **Use Point-Slope Form:**
   Using the point \((-3, 4)\) and the calculated slope \( m = \frac{-11}{6} \), the point-slope form equation is:

   \[
   y - 4 = \frac{-11}{6}(x + 3)
   \]

This represents the equation of the line in point-slope form.
Transcribed Image Text:**Point-Slope Form of a Line** **Problem Statement:** Find the point-slope form of the line passing through the points \((-3, 4)\) and \( (3, -7) \). **Solution:** To find the point-slope form of a line, you need a point on the line and the line's slope. The point-slope form is given by: \[ y - y_1 = m(x - x_1) \] where \( (x_1, y_1) \) is a point on the line and \( m \) is the slope. 1. **Calculate the Slope:** The slope \( m \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Plug in the given points \((-3, 4)\) and \( (3, -7) \): \[ m = \frac{-7 - 4}{3 - (-3)} = \frac{-11}{6} \] 2. **Use Point-Slope Form:** Using the point \((-3, 4)\) and the calculated slope \( m = \frac{-11}{6} \), the point-slope form equation is: \[ y - 4 = \frac{-11}{6}(x + 3) \] This represents the equation of the line in point-slope form.
Expert Solution
Step 1

“Since you have asked multiple question, we will solve the first question for you. If you want any specific question to be solved then please specify the question number or post only that question.”    

Solution Question 4

Given

The inequality 

2xx2-x-60

We have to solve the inequality.

 

steps

Step by step

Solved in 4 steps with 1 images

Blurred answer
Recommended textbooks for you
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781285741550
Author:
James Stewart
Publisher:
Cengage Learning
Thomas' Calculus (14th Edition)
Thomas' Calculus (14th Edition)
Calculus
ISBN:
9780134438986
Author:
Joel R. Hass, Christopher E. Heil, Maurice D. Weir
Publisher:
PEARSON
Calculus: Early Transcendentals (3rd Edition)
Calculus: Early Transcendentals (3rd Edition)
Calculus
ISBN:
9780134763644
Author:
William L. Briggs, Lyle Cochran, Bernard Gillett, Eric Schulz
Publisher:
PEARSON
Calculus: Early Transcendentals
Calculus: Early Transcendentals
Calculus
ISBN:
9781319050740
Author:
Jon Rogawski, Colin Adams, Robert Franzosa
Publisher:
W. H. Freeman
Precalculus
Precalculus
Calculus
ISBN:
9780135189405
Author:
Michael Sullivan
Publisher:
PEARSON
Calculus: Early Transcendental Functions
Calculus: Early Transcendental Functions
Calculus
ISBN:
9781337552516
Author:
Ron Larson, Bruce H. Edwards
Publisher:
Cengage Learning