(2x-1) In(4x) dx

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Question
State the most appropriate technique of integration for this problem, then evaluate the integral.
The integral shown in the image is:

\[ \int (2x - 1) \ln(4x) \, dx \]

This represents the indefinite integral of the function \((2x - 1) \ln(4x)\) with respect to \(x\). In this context, \(\int\) denotes the integral symbol, \(2x - 1\) is the linear term, \(\ln(4x)\) is the natural logarithm of \(4x\), and \(dx\) indicates the variable of integration.

To solve this integral using integration by parts, you'll need to identify parts of the integrand to apply the integration by parts formula:

\[ \int u \, dv = uv - \int v \, du \]

where \(u\) and \(dv\) are chosen from the original integral.
Transcribed Image Text:The integral shown in the image is: \[ \int (2x - 1) \ln(4x) \, dx \] This represents the indefinite integral of the function \((2x - 1) \ln(4x)\) with respect to \(x\). In this context, \(\int\) denotes the integral symbol, \(2x - 1\) is the linear term, \(\ln(4x)\) is the natural logarithm of \(4x\), and \(dx\) indicates the variable of integration. To solve this integral using integration by parts, you'll need to identify parts of the integrand to apply the integration by parts formula: \[ \int u \, dv = uv - \int v \, du \] where \(u\) and \(dv\) are chosen from the original integral.
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