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2x + 1 Evaluate: (За — 1) (22 + 2х + 2) | A F (x) = 2 In (|3x – 1|) + ln (æ² + 2x + 2) – 4 arctan (x + 1) + C 10 F (x) = 2 In (|3x – 1|) – ln (æ² + 2x + 2) – 4 arctan (x + 1) + C 10 F (x) = 2 In (|3x – 1|) – In (x2 + 2x + 2) + 4 arctan (x +1) + C 10 D) F (x) = 2 In (13x – 1|) + In (x² + 2x + 2) + 4 arctan (x+ 1) + C 10 E None of the given choices B.

2x + 1 Evaluate: (За — 1) (22 + 2х + 2) | A F (x) = 2 In (|3x – 1|) + ln (æ² + 2x + 2) – 4 arctan (x + 1) + C 10 F (x) = 2 In (|3x – 1|) – ln (æ² + 2x + 2) – 4 arctan (x + 1) + C 10 F (x) = 2 In (|3x – 1|) – In (x2 + 2x + 2) + 4 arctan (x +1) + C 10 D) F (x) = 2 In (13x – 1|) + In (x² + 2x + 2) + 4 arctan (x+ 1) + C 10 E None of the given choices B.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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2x + 1 dx J (3x – 1) (x2 + 2x + 2) Evaluate: 2 In (|3x – 1|) + In (x² + 2æ + 2) – 4 arctan (x + 1) + C A - F (x) = 10 2 ln (|3x – 1|) – In (x² + 2x + 2) – 4 arctan (x +1) + C - F (x) = 10 © 2 In (|3x – 1|) – In (a2 + 2x + 2) + 4 arctan (x+1) + C - F (x) = %3D 10 (D F (x) = 2 In (|3x – 1|) + In (x2 + 2x + 2) +4 arctan (x + 1) + C 10 E None of the given choices B
Transcribed Image Text:2x + 1 dx J (3x – 1) (x2 + 2x + 2) Evaluate: 2 In (|3x – 1|) + In (x² + 2æ + 2) – 4 arctan (x + 1) + C A - F (x) = 10 2 ln (|3x – 1|) – In (x² + 2x + 2) – 4 arctan (x +1) + C - F (x) = 10 © 2 In (|3x – 1|) – In (a2 + 2x + 2) + 4 arctan (x+1) + C - F (x) = %3D 10 (D F (x) = 2 In (|3x – 1|) + In (x2 + 2x + 2) +4 arctan (x + 1) + C 10 E None of the given choices B
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