2uE F=0 -F = 0 (22) dr2 Note that u, E' and ħ are all positive constants. (f) Using auxiliary equation to solve (22) to show that F = Ae + Be Now we need to apply a boundary condition First we must not allow our solution to contain information about the situation when the particles are free. The particles are free when there is no potential to bound them to each other (i.e. V = + 0). We can see that the potential approaches to 0 when r → 0o. Therefore, the solution must vanish when r 00 Aregr

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A:

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A: False

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A: Curve

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A:

Q: Find the general solution.

A: As per guidelines ,we will solve only first question.

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A:

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A: Use the Gauss’ Divergence theorem,: Use the Gauss’ Divergence theorem,

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A:

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A:

Q: а. у' +3у%38, у(0) %3D4 b. 1 xdx+dy= 0, y(0)=8 y c. senxdx+ ydy=0 y(0)= -2 d. y' +2xy2 = 0, y(0) = 3

A: y = -srqt(2+2cosx) is a solution of:

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A:

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A: True

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A: