-2t x" +6x' +5x = 10t + 30e 2", x(0) = 2, x'(0) = 8 Solve the IVP and find x(0.25) to at least four decimal places of accuracy. Put x(0.25) in the answer box.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
Section: Chapter Questions
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Please solve the following, provide well explained and readable solution. 

 

### Transcription for Educational Website

---

**Differential Equation Problem**

Solve the initial value problem (IVP) given by the differential equation:

\[ x'' + 6x' + 5x = 10t + 30e^{-2t} \]

with the initial conditions: 

\[ x(0) = 2, \quad x'(0) = 8 \]

**Task:**

Find the value of \( x(0.25) \) to at least four decimal places of accuracy. Enter your answer in the provided answer box.

---

### Explanation of Elements:

**Equation Explanation:**

- \( x'' \): The second derivative of \( x \) with respect to \( t \), indicating the acceleration.
- \( 6x' \): The first derivative of \( x \) (velocity) multiplied by 6.
- \( 5x \): The function \( x \) itself multiplied by 5.
- \( 10t + 30e^{-2t} \): The non-homogeneous part of the differential equation, representing a function dependent on \( t \) composed of a linear term and an exponential decay term.

**Initial Conditions:**

- \( x(0) = 2 \): The initial value of the function \( x \) at \( t = 0 \).
- \( x'(0) = 8 \): The initial velocity of the function \( x \) at \( t = 0 \).

**Objective:**

Calculate \( x(0.25) \) accurately and input the result.

---
Transcribed Image Text:### Transcription for Educational Website --- **Differential Equation Problem** Solve the initial value problem (IVP) given by the differential equation: \[ x'' + 6x' + 5x = 10t + 30e^{-2t} \] with the initial conditions: \[ x(0) = 2, \quad x'(0) = 8 \] **Task:** Find the value of \( x(0.25) \) to at least four decimal places of accuracy. Enter your answer in the provided answer box. --- ### Explanation of Elements: **Equation Explanation:** - \( x'' \): The second derivative of \( x \) with respect to \( t \), indicating the acceleration. - \( 6x' \): The first derivative of \( x \) (velocity) multiplied by 6. - \( 5x \): The function \( x \) itself multiplied by 5. - \( 10t + 30e^{-2t} \): The non-homogeneous part of the differential equation, representing a function dependent on \( t \) composed of a linear term and an exponential decay term. **Initial Conditions:** - \( x(0) = 2 \): The initial value of the function \( x \) at \( t = 0 \). - \( x'(0) = 8 \): The initial velocity of the function \( x \) at \( t = 0 \). **Objective:** Calculate \( x(0.25) \) accurately and input the result. ---
Expert Solution
Step 1

Concept Used:-

If roots of characteristics equation is a, b where ab, real

then general solution is   c1eat+c2ebt

Given:- x''+6x'+5x = 10t+30e-2t                                                ...(*)

x(0)=2, x'(0)=8

We first solve the homogeneous equation x''+6x'+5x = 0        ...(1)

So, characteristics equation for (1) is 

r2+6r+5=0(r+1)(r+5)=0r=-1, -5

Thus general solution is 

x(t)=c1e-t+c2e-5t

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