2r2 + y2 7. Consider the equation surface S = P= (1, 1,V3) in the direction of the vector w = (1, 1), corresponds to: An equation for the line tangent to S at the point 1 3 A) (r,y, 2) = (1,1, v3) +t. 3 B) (x, y, 2) = (1, 1, v3) +t. C) (r.y, =) = (1,1, v3) + t- (1,1.) D) (1.y. ) = (1.1. v3) ++ (1,1.). !!
2r2 + y2 7. Consider the equation surface S = P= (1, 1,V3) in the direction of the vector w = (1, 1), corresponds to: An equation for the line tangent to S at the point 1 3 A) (r,y, 2) = (1,1, v3) +t. 3 B) (x, y, 2) = (1, 1, v3) +t. C) (r.y, =) = (1,1, v3) + t- (1,1.) D) (1.y. ) = (1.1. v3) ++ (1,1.). !!
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Please solve by hand
![2r2 + y?
7. Consider the equation surface S =
P= (1, 1,V3) in the direction of the vector w = (1, 1), corresponds to:
An equation for the line tangent to S at the point
%3D
1
3
A) (r, y, 2) = (1,1, v3) +t.
3
B) (r, y, 2) = (1, 1, v3) +t.
C) (r.y, 2) = (1,1, v3) + t (1,1.)
D) (1.y. ) = (1.1. v3) ++ (1,1.).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7757513-3316-44e6-9188-abd594d6f853%2F2057930f-02dc-4dbf-a802-dd60d98d2e29%2Fia4a8h4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:2r2 + y?
7. Consider the equation surface S =
P= (1, 1,V3) in the direction of the vector w = (1, 1), corresponds to:
An equation for the line tangent to S at the point
%3D
1
3
A) (r, y, 2) = (1,1, v3) +t.
3
B) (r, y, 2) = (1, 1, v3) +t.
C) (r.y, 2) = (1,1, v3) + t (1,1.)
D) (1.y. ) = (1.1. v3) ++ (1,1.).
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