2π The figure to the right shows four regions bounded by the graph of y=x sin x: R1, R2, R3, and R4, whose areas are 1, л-1, л+1, and 2-1, respectively. Use this information to evaluate the following integral. 2π S x sin x dx 3л/2 x sin x dx = 3л/2 YA Area = 1 2 y = x sin x R₁! R₂ + 플 Area =-1 E ☐ (Type an exact answer, using л as needed.) Area = +1 2 R3 R4 Area = 2-1

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